ACM——homo分瓜意义不明的偶数

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

#include <iostream>
using namespace std;

//能拆成偶加偶，两个偶数相加，一定是偶数呀
//一个偶数，一定可以拆成两个偶数相加（除了2）
//这个题在问什么呢
//x/2如果为偶数，就是两个相同偶数相加，为奇数,就是x+1,x-1
bool judge(int n)
{
	return n % 2 == 0 && n != 2;
}
int main()
{
	int n; cin >> n;
	if (judge(n)) cout << "YES";
	else cout << "NO";
	return 0;
}