将‘林’替换成‘燕’
create table #blogUser(
username nvarchar(15),
password nvarchar(10) )
insert into #blogUser values('林林','123')
insert into #blogUser values('陈东林','123')
insert into #blogUser values('李林','123')
insert into #blogUser values('张东三','123')
insert into #blogUser values('张东东','123')
update #blogUser set username=case charindex('林',username)
when 1 then '燕'+ substring(username,2,len(username))
else substring(username, 1, charindex('林',username)-1) + '燕' + substring(username, charindex('林',username)+1, len(username)-charindex('林',username))
end
where username like '%林%'
select * from #blogUser
效果如下所示:
username password
燕林 123
陈东燕 123
李燕 123
张东三 123
张东东 123