android得到两个时间的long[]值

最新推荐文章于 2023-06-30 17:06:57 发布

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本文介绍了两种计算两个时间戳之间差值的方法。第一种方法使用SimpleDateFormat解析日期字符串，并计算差值转换为天、小时、分钟和秒。第二种方法采用常量定义，通过比较时间差与一天、一小时、一分钟的秒数来计算具体的时间差。

第一种方法

/**
     * 两个时间相差距离多少天多少小时多少分多少秒
     * @param str1 时间参数 1 格式：1990-01-01 12:00:00
     * @param str2 时间参数 2 格式：2009-01-01 12:00:00
     * @return long[] 返回值为：{天, 时, 分, 秒}
     */
    public static long[] getTwoDateDifferenceDates(String str1, String str2) {
        DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        Date one;
        Date two;
        long day = 0;
        long hour = 0;
        long min = 0;
        long sec = 0;
        try {
            one = df.parse(str1);
            two = df.parse(str2);
            long time1 = one.getTime();
            long time2 = two.getTime();
            long diff ;
            if(time1<time2) {
                diff = time2 - time1;
            } else {
                diff = time1 - time2;
            }
            day = diff / (24 * 60 * 60 * 1000);
            hour = (diff / (60 * 60 * 1000) - day * 24);
            min = ((diff / (60 * 1000)) - day * 24 * 60 - hour * 60);
            sec = (diff/1000-day*24*60*60-hour*60*60-min*60);
        } catch (ParseException e) {
            e.printStackTrace();
        }
        long[] times = {day, hour, min, sec};
        return times;
    }

第二种方法

private static final long ONE_MINUTE = 60;
private static final long ONE_HOUR = 3600;
private static final long ONE_DAY = 86400;
private static final long ONE_MONTH = 2592000;
private static final long ONE_YEAR = 31104000;

public static long[] absolutlyFromToday(long time){
        long day =0;
        long hour = 0;
        long minute = 0;
        long second = 0;
        if (time<ONE_MINUTE){
            second = time;
        }else if (time <ONE_HOUR){
            minute = time/ONE_MINUTE;
            second = time%ONE_MINUTE;
        }else if(time<ONE_DAY){
            hour = time/ONE_HOUR;
            long reside = time%ONE_HOUR;
            minute = reside/ONE_MINUTE;
            second = reside%ONE_MINUTE;
        }else{
            day = time/ONE_DAY;
            long reside = time%ONE_DAY;
            hour = reside/ONE_HOUR;
            long reside1 = reside%ONE_HOUR;
            minute = reside1/ONE_MINUTE;
            second = reside1%ONE_MINUTE;
        }
        return new long[]{day,hour,minute,second};
    }

可以拿着long[]操作任何时间相关

public void setTimes(long[] times) {
        mday = times[0];
        mhour = times[1];
        mmin = times[2];
        msecond = times[3];
    }