python 实现 windows 自带计算器（标准）功能

做了一个超级简单浓缩版计算器，没有贴图什么的

实现效果：

import tkinter as tk


class Jisuanqi:
    def __init__(self, master):
        self.master = master
        master.title("计算器")

        self.result_text = tk.StringVar()
        self.result_text.set("0")
        self.entry = tk.Entry(master, textvariable=self.result_text, justify='right', font=('Arial', 20))
        self.entry.grid(row=0, column=0, columnspan=4, sticky='nsew')

        button_texts = [
            '7', '8', '9', '/',
            '4', '5', '6', '*',
            '1', '2', '3', '-',
            '0', '.', '=', '+'
        ]

        row_num = 1
        col_num = 0
        for text in button_texts:
            button = tk.Button(master, text=text, font=('Arial', 16), command=lambda t=text: self.button_click(t))
            button.grid(row=row_num, column=col_num, sticky='nsew')
            col_num += 1
            if col_num > 3:
                col_num = 0
                row_num += 1

        master.bind('<Key>', self.keyboard_click)

    def button_click(self, value):
        current_text = self.result_text.get()

        if value == '=':
            try:
                result = eval(current_text)
                self.result_text.set(str(result))
            except:
                self.result_text.set("错误")
        elif value == 'C':
            self.result_text.set("0")
        else:
            if current_text == "0":
                self.result_text.set(value)
            else:
                self.result_text.set(current_text + value)

    def keyboard_click(self, event):
        value = event.char
        if value.isdigit() or value in ['+', '-', '*', '/', '.', '=', '\r']:
            self.button_click(value)


if __name__ == "__main__":
    root = tk.Tk()
    app = Jisuanqi(root)
    root.mainloop()