Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +
, -
, *
, /
. Each operand may be an integer or another expression.
Note:
- Division between two integers should truncate toward zero.
- The given RPN expression is always valid. That means the expression would always evaluate to a result and there won't be any divide by zero operation.
Example 1:
Input: ["2", "1", "+", "3", "*"] Output: 9 Explanation: ((2 + 1) * 3) = 9
Example 2:
Input: ["4", "13", "5", "/", "+"] Output: 6 Explanation: (4 + (13 / 5)) = 6
Example 3:
Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"] Output: 22 Explanation: ((10 * (6 / ((9 + 3) * -11))) + 17) + 5 = ((10 * (6 / (12 * -11))) + 17) + 5 = ((10 * (6 / -132)) + 17) + 5 = ((10 * 0) + 17) + 5 = (0 + 17) + 5 = 17 + 5 = 22
class Solution {
private:
set<string> operators = {"+","-","*","/"};
stack<int> sk_rpn;
public:
int evalRPN(vector<string>& tokens) {
if(!tokens.size())
return 0;
for(int i=0; i<tokens.size(); i++)
{
if(operators.find(tokens[i])==operators.end())
{
sk_rpn.push(atoi(tokens[i].c_str()));
}else
{
if(tokens[i].compare("+")==0)
{
int num2 = sk_rpn.top();
sk_rpn.pop();
int num1 = sk_rpn.top();
sk_rpn.pop();
int result = num1 + num2;
sk_rpn.push(result);
}else if(tokens[i].compare("-")==0)
{
int num2 = sk_rpn.top();
sk_rpn.pop();
int num1 = sk_rpn.top();
sk_rpn.pop();
int result = num1 - num2;
sk_rpn.push(result);
}else if(tokens[i].compare("*")==0)
{
int num2 = sk_rpn.top();
sk_rpn.pop();
int num1 = sk_rpn.top();
sk_rpn.pop();
int result = num1 * num2;
sk_rpn.push(result);
}else if(tokens[i].compare("/")==0)
{
int num2 = sk_rpn.top();
sk_rpn.pop();
int num1 = sk_rpn.top();
sk_rpn.pop();
int result = num1 / num2;
sk_rpn.push(result);
}
}
}
int result = sk_rpn.top();
sk_rpn.pop();
return result;
}
};