记忆化搜索,跟以前的做过的 滑雪 一样的。
DP+DFS。用dp[][]保存搜索记录,然后满足条件累加即可。
#include<cstdio>
#include<cstring>
#include<string>
#include<queue>
#include<algorithm>
#include<map>
#include<stack>
#include<iostream>
#include<list>
#include<set>
#include<bitset>
#include<vector>
#include<cmath>
#define INF 0x7fffffff
#define eps 1e-8
#define LL long long
#define PI 3.141592654
#define CLR(a,b) memset(a,b,sizeof(a))
#define FOR(i,a,b) for(int i=a;i<b;i++)
#define FOR_(i,a,b) for(int i=a;i>=b;i--)
#define pub push_back
#define puf push_front
#define pob pop_back
#define pof pop_front
#define mp make_pair
#define ft first
#define sd second
#define sf scanf
#define pf printf
#define sz(v) ((int)(v).size())
#define all(v) (v).begin(),(v).end()
#define acfun std::ios::sync_with_stdio(false)
#define SIZE 100 +1
using namespace std;
int n,m;
int g[SIZE][SIZE];
int xx[]={0,0,-1,1};
int yy[]={-1,1,0,0};
int dp[SIZE][SIZE];
int dfs(int i,int j)
{
if(dp[i][j]>1)return dp[i][j];
FOR(k,0,4)
{
int x=i+xx[k];
int y=j+yy[k];
if(x<0||y<0||x>=n||y>=m)continue;
if(g[x][y]<g[i][j])
dp[i][j]=max(dp[i][j],dfs(x,y)+1);
}
return dp[i][j];
}
int main()
{
int t;
sf("%d",&t);
while(t--)
{
char str[SIZE];
sf("%s%d%d",str,&n,&m);
FOR(i,0,n)
FOR(j,0,m)
sf("%d",&g[i][j]),dp[i][j]=1;
int ans=0;
FOR(i,0,n)
FOR(j,0,m)
ans=max(ans,dfs(i,j));
pf("%s: %d\n",str,ans);
}
}