AtCoder Beginner Contest 227

ABC227A Last Card

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#include <bits/stdc++.h>
using namespace std;
int n,k,a;
int main()
{
	cin>>n>>k>>a;
	k-=(n-a+1);
	if(k%n==0)cout<<n;
	else cout<<k%n;
	return 0;
}

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 输入一组数据，就明白为什么没有AC了

691 60 43

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输出的结果为-589

为什么会这样呢

将上面的数据代入公式 

n=691
k=60
a=43
k-=(n-a+1);

n-a+1
=n-(a-1)
=691-(43-1)
=649

k-=649
k=60-649
=-589

参考下面博客：

【转】C/C++除法实现方式及负数取模详解

【转】C/C++除法实现方式及负数取模详解 - lucas hsueh - 博客园

 C/C++ 取模的正负和被除数的正负相对应，

也就是说，比如a%b

a为负数，则a%b的结果为负数

a为正数，则a%b的结果为正数

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本题更好的题解程序见下面博客：

AtCoder Beginner Contest 227（A-F）好

AtCoder Beginner Contest 227（A-F）_atcoder beginner contest 227 c - abc conjecture-优快云博客

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