Problem G: 平面上的点和线——Point类、Line类 (III)

Description

在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定，两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。

根据“append.cc”，完成Point类和Line类的构造方法和show()方法，输出各Line对象和Point对象的构造和析构次序。

接口描述：

Point::show()方法：按格式输出Point对象。

Line::show()方法：按格式输出Line对象。

Input

输入的第一行为N，表示后面有N行测试样例。每行为两组坐标“x,y”，分别表示线段起点和终点的x坐标和y坐标，两组坐标间用一个空格分开，x和y的值都在double数据范围内。

Output

输出为多行，每行为一条线段，起点坐标在前终点坐标在后，每个点的X坐标在前，Y坐标在后，Y坐标前面多输出一个空格，用括号包裹起来。输出格式见sample。

C语言的输入输出被禁用。

Sample Input

4

0,0 1,1

1,1 2,3

2,3 4,5

0,1 1,0

Sample Output

Point : (1, -2) is created.

Point : (2, -1) is created.

Point : (0, 0) is created.

Point : (0, 0)

=========================

Point : (0, 0) is created.

Point : (1, 1) is created.

Line : (0, 0) to (1, 1) is created.

Line : (0, 0) to (1, 1)

Line : (0, 0) to (1, 1) is erased.

Point : (1, 1) is erased.

Point : (0, 0) is erased.

=========================

Point : (1, 1) is created.

Point : (2, 3) is created.

Line : (1, 1) to (2, 3) is created.

Line : (1, 1) to (2, 3)

Line : (1, 1) to (2, 3) is erased.

Point : (2, 3) is erased.

Point : (1, 1) is erased.

=========================

Point : (2, 3) is created.

Point : (4, 5) is created.

Line : (2, 3) to (4, 5) is created.

Line : (2, 3) to (4, 5)

Line : (2, 3) to (4, 5) is erased.

Point : (4, 5) is erased.

Point : (2, 3) is erased.

=========================

Point : (0, 1) is created.

Point : (1, 0) is created.

Line : (0, 1) to (1, 0) is created.

Line : (0, 1) to (1, 0)

Line : (0, 1) to (1, 0) is erased.

Point : (1, 0) is erased.

Point : (0, 1) is erased.

=========================

Point : (1, -2) is copied.

Point : (2, -1) is copied.

Line : (1, -2) to (2, -1) is created.

Point : (1, -2) is copied.

Point : (0, 0) is copied.

Line : (1, -2) to (0, 0) is created.

Point : (2, -1) is copied.

Point : (0, 0) is copied.

Line : (2, -1) to (0, 0) is created.

Point : (0, 0) is copied.

Point : (2, -1) is copied.

Line : (0, 0) to (2, -1) is created.

Line : (1, -2) to (2, -1)

Line : (1, -2) to (0, 0)

Line : (2, -1) to (0, 0)

Line : (0, 0) to (2, -1)

Line : (0, 0) to (2, -1) is erased.

Point : (2, -1) is erased.

Point : (0, 0) is erased.

Line : (2, -1) to (0, 0) is erased.

Point : (0, 0) is erased.

Point : (2, -1) is erased.

Line : (1, -2) to (0, 0) is erased.

Point : (0, 0) is erased.

Point : (1, -2) is erased.

Line : (1, -2) to (2, -1) is erased.

Point : (2, -1) is erased.

Point : (1, -2) is erased.

Point : (0, 0) is erased.

Point : (2, -1) is erased.

Point : (1, -2) is erased.

HINT

Append Code

#include<iostream>

using namespace std;

class Point

{

private :

     double x,y;

public :

     Point( double a=0, double b=0):x(a),y(b){cout<< "Point : (" <<x<< ", " <<y<< ") is created." <<endl;}

     ~Point(){cout<< "Point : (" <<x<< ", " <<y<< ") is erased." <<endl;}

     Point( const Point &q){x=q.x;y=q.y;cout<< "Point : (" <<x<< ", " <<y<< ") is copied." <<endl;}

     double getX(){ return x;}

     double getY(){ return y;}

     void show(){cout<< "Point : (" <<x<< ", " <<y<< ")" <<endl;}

};

class Line

{

private :

     Point xx,yy;

public :

     Line( double a, double b, double c, double d):xx(a,b),yy(c,d){cout<< "Line : (" <<xx.getX()<< ", " <<xx.getY()<< ") to (" <<yy.getX()<< ", " <<yy.getY()<< ") is created." <<endl;}

      Line(Point &a,Point &b):xx(a),yy(b){cout<< "Line : (" <<xx.getX()<< ", " <<xx.getY()<< ") to (" <<yy.getX()<< ", " <<yy.getY()<< ") is created." <<endl;}

     void show(){cout<< "Line : (" <<xx.getX()<< ", " <<xx.getY()<< ") to (" <<yy.getX()<< ", " <<yy.getY()<< ")" <<endl;}

     ~Line(){cout<< "Line : (" <<xx.getX()<< ", " <<xx.getY()<< ") to (" <<yy.getX()<< ", " <<yy.getY()<< ") is erased." <<endl;}

};

int main()

{

     char c;

     int num, i;

     double x1, x2, y1, y2;

     Point p(1, -2), q(2, -1), t;

     t.show();

     std::cin>>num;

     for (i = 1; i <= num; i++)

     {

         std::cout<< "=========================\n" ;

         std::cin>>x1>>c>>y1>>x2>>c>>y2;

         Line line(x1, y1, x2, y2);

         line.show();

     }

     std::cout<< "=========================\n" ;

     Line l1(p, q), l2(p, t), l3(q, t), l4(t, q);

     l1.show();

     l2.show();

     l3.show();

     l4.show();

}

转载于:https://www.cnblogs.com/TogetherLaugh/p/6544764.html