【luogu P3258 [JLOI2014]松鼠的新家】 题解

本文通过洛谷P3258题目的解答,介绍了如何使用树剖分和线段树解决复杂路径查询问题。文章展示了完整的C++代码实现,并详细解释了树剖分预处理、线段树维护节点更新及区间查询等关键步骤。

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题目链接:https://www.luogu.org/problemnew/show/P3258

谁说树剖过不去会RE呢?

我今天就是要强行树剖了

树剖强艹

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#define ll long long
using namespace std;
const int maxn = 500010;
ll ans[maxn], son[maxn], deep[maxn], size[maxn], fa[maxn], top[maxn], seg[maxn], num, n, m, path[maxn];
struct edge{
    ll to, next;
}e[maxn<<2];
ll head[maxn], cnt;
void add(ll u, ll v)
{
    e[++cnt].to = v; e[cnt].next = head[u]; head[u] = cnt;
    e[++cnt].to = u; e[cnt].next = head[v]; head[v] = cnt;
}
class Segment_Tree{
    public:
        #define lson l, mid, rt<<1
        #define rson mid+1, r, rt<<1|1
        ll tree[maxn<<2], lazy[maxn<<2];
        void build(ll l, ll r, ll rt)
        {
            if(l == r)
            {
                tree[rt] = 0;
                return;
            }
            ll mid = (l + r) >> 1;
            build(lson);
            build(rson);
            PushUP(rt);
        }
        void update(ll left, ll right, ll add, ll l, ll r, ll rt)
        {
            if(left <= l && right >= r)
            {
                lazy[rt] += add;
                tree[rt] += (r - l + 1) * add;
                return;
            }
            ll mid = (l + r) >> 1;
            PushDOWN(l, r, rt);
            if(left <= mid) update(left, right, add, lson);
            if(right > mid) update(left, right, add, rson);
            PushUP(rt);
        }
        ll query(ll left, ll right, ll l, ll r, ll rt)
        {
            ll res = 0;
            if(left <= l && right >= r)
            {
                return tree[rt];
            }
            ll mid = (l + r) >> 1;
            PushDOWN(l, r, rt);
            if(left <= mid) res += query(left, right, lson);
            if(right > mid) res += query(left, right, rson);
            return res;
        }
    private:
        void PushUP(ll rt)
        {
            tree[rt] = tree[rt<<1] + tree[rt<<1|1];
        }
        void PushDOWN(ll l, ll r, ll rt)
        {
            ll mid = (l + r) >> 1;
            if(lazy[rt])
            {
                lazy[rt<<1] += lazy[rt];
                lazy[rt<<1|1] += lazy[rt];
                tree[rt<<1] += (mid-l+1)*lazy[rt];
                tree[rt<<1|1] += (r-mid)*lazy[rt];
                lazy[rt] = 0;
            }
        }
}T;
void dfs1(ll u, ll f, ll d)
{
    ll maxson = -1;
    size[u] = 1;
    deep[u] = d;
    fa[u] = f;
    for(ll i = head[u]; i != -1; i = e[i].next)
    {
        ll v = e[i].to;
        if(f != v)
        {
            dfs1(v, u, d+1);
            size[u] += size[v];
            if(size[v] > maxson) son[u] = v, maxson = size[v];
        }
    }
}
void dfs2(ll u, ll t)
{
    seg[u] = ++num;
    top[u] = t;
    if(!son[u]) return;
    dfs2(son[u], t);
    for(ll i = head[u]; i != -1; i = e[i].next)
    {
        ll v = e[i].to;
        if(v == son[u] || v == fa[u]) continue;
        dfs2(v, v);
    }
}
ll LCA(ll x, ll y)
{
    while(top[x] != top[y])
    {
        if(deep[top[x]] < deep[top[y]]) swap(x, y);
        x = fa[top[x]];
    }
    return deep[x] < deep[y] ? x : y;
}
ll Qson(ll x)
{
    ll res = 0;
    res += T.query(seg[x], seg[x]+size[x]-1, 1, n, 1);
    return res;
}
void Updson(ll x, ll y)
{
    T.update(seg[x], seg[x]+size[x]-1, y, 1, n, 1);
}
ll Qrange(ll x, ll y)
{
    ll res = 0;
    while(top[x] != top[y])
    {
        if(deep[top[x]] < deep[top[y]]) swap(x, y);
        res += T.query(seg[top[x]], seg[x], 1, n, 1);
        x = fa[top[x]];
    }
    if(deep[x] < deep[y]) swap(x, y);
    res += T.query(seg[y], seg[x], 1, n, 1);
    return res;
}
void Updrange(ll x, ll y, ll z)
{
    while(top[x] != top[y])
    {
        if(deep[top[x]] < deep[top[y]]) swap(x, y);
        T.update(seg[top[x]], seg[x], z, 1, n, 1);
        x = fa[top[x]];
    }
    if(deep[x] < deep[y]) swap(x, y);
    T.update(seg[y], seg[x], z, 1, n, 1);
}
int main()
{
    memset(head, -1, sizeof(head));
    scanf("%lld%lld",&n,&path[1]);
    for(ll i = 2; i <= n; i++)
    {
        scanf("%lld",&path[i]);
        ans[path[i]]--;
    }
    for(ll i = 1; i <= n-1; i++)
    {
        ll u, v;
        scanf("%lld%lld",&u,&v);
        add(u, v);
    }
    dfs1(1, 0, 1); dfs2(1, 1);
    T.build(1, n, 1);
    for(ll i = 2; i <= n; i++)
    {
        Updrange(path[i], path[i-1], 1);
    }
    for(ll i = 1; i <= n; i++) ans[i] += Qrange(i, i);
    for(ll i = 1; i <= n; i++)
    {
        printf("%lld\n",ans[i]);
    }
    return 0;
}

转载于:https://www.cnblogs.com/MisakaAzusa/p/9877301.html

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