点权模板:
1、M a b c将节点a到节点b路径上所有点都染成颜色c;
2、Q a b询问节点a到节点b路径上的颜色段数量(连续相同颜色被认为是同一段),如“112221”由3段组成:“11”、“222”和“1”。
const int N = 100100;
struct edge
{
int to, next;
}g[N*2];
int cnt, head[N];
int dep[N], siz[N], son[N], fat[N], id[N], top[N];
int color[N], d[N][2], pos[N];
int n, m, num;
struct node
{
int l, r, lc, rc, val, mark; /*lc, rc记录区间左端点和右端点颜色,*/
}tr[N*4];
void init()
{
cnt = 0;
memset(head, -1, sizeof head);
num = 0;
}
void add_edge(int v, int u)
{
g[cnt].to = u, g[cnt].next = head[v], head[v] = cnt++;
}
void dfs1(int v, int fa, int d)
{
dep[v] = d, son[v] = 0, siz[v] = 1, fat[v] = fa;
for(int i = head[v]; i != -1; i = g[i].next)
{
int u = g[i].to;
if(u != fa)
{
dfs1(u, v, d + 1);
siz[v] += siz[u];
if(siz[son[v]] < siz[u]) son[v] = u;
}
}
}
void dfs2(int v, int tp)
{
top[v] = tp, id[v] = ++num;
if(son[v]) dfs2(son[v], top[v]);
for(int i = head[v]; i != -1; i = g[i].next)
{
int u = g[i].to;
if(u != fat[v] && u != son[v]) dfs2(u, u);
}
}
void push_up(int k)
{ /*区间合并,判断左儿子的右端点和右儿子的左端点是否相同,更新父节点左右端点颜色*/
tr[k].lc = tr[k<<1].lc, tr[k].rc = tr[k<<1|1].rc;
if(tr[k<<1].rc == tr[k<<1|1].lc)
tr[k].val = tr[k<<1].val + tr[k<<1|1].val - 1;
else tr[k].val = tr[k<<1].val + tr[k<<1|1].val;
}
void push_down(int k)
{
if(tr[k].mark)
{
tr[k<<1].mark = tr[k<<1|1].mark = tr[k].mark;
tr[k<<1].lc = tr[k<<1].rc = tr[k<<1|1].lc = tr[k<<1|1].rc = tr[k].mark;
tr[k<<1].val = tr[k<<1|1].val = 1;
tr[k].mark = 0;
}
}
void build(int l, int r, int k)
{
tr[k].l = l, tr[k].r = r, tr[k].val = 1, tr[k].mark = 0;
if(l == r)
{
tr[k].lc = tr[k].rc = pos[l];
return;
}
int mid = (l + r) >> 1;
build(l, mid, k << 1);
build(mid + 1, r, k << 1|1);
push_up(k);
}
void update(int l, int r, int c, int k)
{
if(l <= tr[k].l && tr[k].r <= r)
{
tr[k].val = 1;
tr[k].lc = tr[k].rc = c;
tr[k].mark = c;
return;
}
push_down(k);
int mid = (tr[k].l + tr[k].r) >> 1;
if(l <= mid) update(l, r, c, k << 1);
if(r > mid) update(l, r, c, k << 1|1);
push_up(k);
}
int query(int l, int r, int k)
{
if(l <= tr[k].l && tr[k].r <= r) return tr[k].val;
push_down(k);
int mid = (tr[k].l + tr[k].r) >> 1;
int ans = 0, f1 = 0, f2 = 0;
if(l <= mid)
ans += query(l, r, k << 1), f1 = 1;
if(r > mid)
ans += query(l, r, k << 1|1), f2 = 1;
if(f1 && f2) /*查询时注意判断相邻两个区间相接处颜色是否相同*/
if(tr[k<<1].rc == tr[k<<1|1].lc) ans -= 1;
return ans;
//注释掉的另一种查询
// if(r <= mid) return query(l, r, k << 1);
// else if(l > mid) return query(l, r, k << 1|1);
// else
// {
// int ans = 0;
// ans = query(l, r, k << 1) + query(l, r, k << 1|1);
// if(tr[k<<1].rc == tr[k<<1|1].lc) ans -= 1;
// return ans;
// }
}
int query_node(int x, int k)
{
if(tr[k].l == tr[k].r) return tr[k].rc;
push_down(k);
int mid = (tr[k].l + tr[k].r) >> 1;
int ans = 0;
if(x <= mid) ans = query_node(x, k << 1);
else ans = query_node(x, k << 1|1);
push_up(k);
return ans;
}
void Update(int v, int u, int c)
{
int t1 = top[v], t2 = top[u];
while(t1 != t2)
{
if(dep[t1] < dep[t2])
swap(t1, t2), swap(v, u);
update(id[t1], id[v], c, 1);
v = fat[t1], t1 = top[v];
}
//和边权不同的地方
if(dep[v] > dep[u]) swap(v, u);
update(id[v], id[u], c, 1);
}
int Query(int v, int u)
{
int t1 = top[v], t2 = top[u];
int ans = 0;
while(t1 != t2)
{
if(dep[t1] < dep[t2])
swap(t1, t2), swap(v, u);
ans += query(id[t1], id[v], 1);
/*判断相邻两个区间相接处颜色是否相同*/
if(query_node(id[t1], 1) == query_node(id[fat[t1]], 1)) ans--;
v = fat[t1], t1 = top[v];
}
//和边权不同的地方
if(dep[v] > dep[u]) swap(v, u);
return ans += query(id[v], id[u], 1);
}
int main()
{
while(~ scanf("%d%d", &n, &m))
{
init();
for(int i = 1; i <= n; i++)
scanf("%d", &color[i]);
for(int i = 1; i <= n - 1; i++)
{
scanf("%d%d", &d[i][0], &d[i][1]);
add_edge(d[i][0], d[i][1]);
add_edge(d[i][1], d[i][0]);
}
dfs1(1, 0, 1);
dfs2(1, 1);
for(int i = 1; i <= n; i++) pos[id[i]] = color[i];
build(1, num, 1);
char ch;
int a, b, c;
while(m--)
{
scanf(" %c", &ch);
if(ch == 'Q')
{
scanf("%d%d", &a, &b);
printf("%d\n", Query(a, b));
}
else
{
scanf("%d%d%d", &a, &b, &c);
Update(a, b, c);
}
}
}
return 0;
}
边权模板:
const int N = 100100;
struct edge
{
int to, next;
}g[N*2];
int cnt, head[N];
int dep[N], siz[N], son[N], fat[N], id[N], top[N];
int d[N][3], pos[N];
int n, m, num;
struct node
{
int l, r, lc, rc, val, mark;
}tr[N*4];
void add_edge(int v, int u)
{
g[cnt].to = u, g[cnt].next = head[v], head[v] = cnt++;
}
void dfs1(int v, int fa, int d)
{
dep[v] = d, son[v] = 0, siz[v] = 1, fat[v] = fa;
for(int i = head[v]; i != -1; i = g[i].next)
{
int u = g[i].to;
if(u != fa)
{
dfs1(u, v, d + 1);
siz[v] += siz[u];
if(siz[son[v]] < siz[u]) son[v] = u;
}
}
}
void dfs2(int v, int tp)
{
top[v] = tp, id[v] = ++num;
if(son[v]) dfs2(son[v], top[v]);
for(int i = head[v]; i != -1; i = g[i].next)
{
int u = g[i].to;
if(u != fat[v] && u != son[v]) dfs2(u, u);
}
}
void push_up(int k)
{
tr[k].lc = tr[k<<1].lc, tr[k].rc = tr[k<<1|1].rc;
if(tr[k<<1].rc == tr[k<<1|1].lc)
tr[k].val = tr[k<<1].val + tr[k<<1|1].val - 1;
else tr[k].val = tr[k<<1].val + tr[k<<1|1].val;
}
void push_down(int k)
{
if(tr[k].mark)
{
tr[k<<1].mark = tr[k<<1|1].mark = tr[k].mark;
tr[k<<1].lc = tr[k<<1].rc = tr[k<<1|1].lc = tr[k<<1|1].rc = tr[k].mark;
tr[k<<1].val = tr[k<<1|1].val = 1;
tr[k].mark = 0;
}
}
void build(int l, int r, int k)
{
tr[k].l = l, tr[k].r = r, tr[k].val = 1, tr[k].mark = 0;
if(l == r)
{
tr[k].lc = tr[k].rc = pos[l];
return;
}
int mid = (l + r) >> 1;
build(l, mid, k << 1);
build(mid + 1, r, k << 1|1);
push_up(k);
}
void update(int l, int r, int c, int k)
{
if(l <= tr[k].l && tr[k].r <= r)
{
tr[k].val = 1;
tr[k].lc = tr[k].rc = c;
tr[k].mark = c;
return;
}
push_down(k);
int mid = (tr[k].l + tr[k].r) >> 1;
if(l <= mid) update(l, r, c, k << 1);
if(r > mid) update(l, r, c, k << 1|1);
push_up(k);
}
int query(int l, int r, int k)
{
if(l <= tr[k].l && tr[k].r <= r) return tr[k].val;
push_down(k);
int mid = (tr[k].l + tr[k].r) >> 1;
int ans = 0, f1 = 0, f2 = 0;
if(l <= mid)
ans += query(l, r, k << 1), f1 = 1;
if(r > mid)
ans += query(l, r, k << 1|1), f2 = 1;
if(f1 && f2)
if(tr[k<<1].rc == tr[k<<1|1].lc) ans -= 1;
return ans;
}
int query_node(int x, int k)
{
if(tr[k].l == tr[k].r) return tr[k].rc;
push_down(k);
int mid = (tr[k].l + tr[k].r) >> 1;
int ans = 0;
if(x <= mid) ans = query_node(x, k << 1);
else ans = query_node(x, k << 1|1);
return ans;
}
void Update(int v, int u, int c)
{
int t1 = top[v], t2 = top[u];
while(t1 != t2)
{
if(dep[t1] < dep[t2])
swap(t1, t2), swap(v, u);
update(id[t1], id[v], c, 1);
v = fat[t1], t1 = top[v];
}
if(v == u) return;
if(dep[v] > dep[u]) swap(v, u);
update(id[son[v]], id[u], c, 1);
}
int Query(int v, int u)
{//Query函数和Update函数基本是相同的,Query函数里面多出来的是此题的代码,不是通用代码,参照Update函数
int t1 = top[v], t2 = top[u];
int ans = 0;
int cv = 0, cu = 0, x;
while(t1 != t2)
{
if(dep[t1] < dep[t2])
swap(t1, t2), swap(v, u), swap(cu, cv);
ans += query(id[t1], id[v], 1);
x = query_node(id[v], 1);//查询当前链的尾端颜色
if(x == cv) ans--; //如果和当前链的前一段链的首端颜色一样,则-1
cv = query_node(id[t1], 1);//查询并记录当前链的首端颜色
v = fat[t1], t1 = top[v];
}
if(v == u)
{
if(cv == cu) ans--;
return ans;
}
/*此处特别判断,比如u是根节点,v到根节点路径是一段连续的重链*/
if(dep[v] > dep[u]) swap(v, u), swap(cv, cu);
ans += query(id[son[v]], id[u], 1);
//最后查询的这条链和两条链相接,所以都要判断相接处颜色是否相同
x = query_node(id[u], 1);
if(x == cu) ans--;
x = query_node(id[son[v]], 1);
if(x == cv) ans--;
return ans;
}
int main()
{
char str[100];
int a, b, c;
while(~ scanf("%d%d", &n, &m))
{
cnt = num = 0;
memset(head, -1, sizeof head);
for(int i = 1; i <= n - 1; i++)
{
scanf("%d%d%d", &d[i][0], &d[i][1], &d[i][2]);
add_edge(d[i][0], d[i][1]), add_edge(d[i][1], d[i][0]);
}
dfs1(1, 0, 1);
dfs2(1, 1);
for(int i = 1; i <= n - 1; i++)
{//把边关联到深度较深的端点上,更新第i条边时,即更新id[d[i][1]];
if(dep[d[i][0]] > dep[d[i][1]]) swap(d[i][0], d[i][1]);
pos[id[d[i][1]]] = d[i][2];
}
build(1, num, 1);
for(int i = 1; i <= m; i++)
{
scanf(" %s", str);
if(str[0] == 'Q')
{
scanf("%d%d", &a, &b);
printf("%d\n", Query(a, b));
}
else
{
scanf("%d%d%d", &a, &b, &c);
Update(a, b, c);
}
}
}
return 0;
}