HDU4320——GCD——Arcane Numbers 1

http://acm.hdu.edu.cn/showproblem.php?pid=4320

/*
公式：两个进制能相互转化，那么这两个进制的最小因数相同
*/
/************************************************
* Author        :Powatr
* Created Time  :2015-8-25 14:49:53
* File Name     :A.cpp
 ************************************************/

#include <cstdio>
#include <algorithm>
#include <iostream>
#include <sstream>
#include <cstring>
#include <cmath>
#include <string>
#include <vector>
#include <queue>
#include <deque>
#include <stack>
#include <list>
#include <map>
#include <set>
#include <bitset>
#include <cstdlib>
#include <ctime>
using namespace std;

#define lson l, mid, rt << 1
#define rson mid + 1, r, rt << 1 | 1
typedef long long ll;
const int MAXN = 1e5 + 10;
const int INF = 0x3f3f3f3f;
const int MOD = 1e9 + 7;

long long a, b;
long long  gcd(long long a, long long b)
{
    return b == 0 ? a : gcd(b, a%b);
}
int main()
{
    int T;
    scanf("%d", &T);
    for(int cas = 1; cas <= T; cas++){
        scanf("%I64d%I64d", &a, &b);
        long long  c = gcd(a, b);
        long long  d;
        a /= c, b /= c;
        int flag = 1;
        while(1){
            if(b == 1) break;
            d = gcd(b, c);
            if(d == 1){
                flag = 0;
                break;
            }
            b /= d;
        }
        while(1){
            if(a == 1) break;
            d = gcd(a, c);
            if(d == 1){
                flag = 0;
                break;
            }
            a /= d;
        }
        printf("Case #%d: %s\n", cas, flag == 1 ? "YES" : "NO");
    }
    return 0;
}
            

　　

转载于:https://www.cnblogs.com/zero-begin/p/4757487.html