c语言 int与byte[]互相转换

最新推荐文章于 2025-05-26 20:24:16 发布

新生代CV搬运工

最新推荐文章于 2025-05-26 20:24:16 发布

阅读量1.5w

点赞数 2

CC 4.0 BY-SA版权

分类专栏： c linux 文章标签： c语言 int2byte byte2int linux gdb

本文链接：https://blog.youkuaiyun.com/devwang_com/article/details/53348891

linux 同时被 2 个专栏收录

35 篇文章

订阅专栏

10 篇文章

订阅专栏

本文介绍了一个C语言程序，该程序演示了如何将int类型的数据转换为byte数组以及如何从byte数组还原回int类型。通过使用位操作和内存分配函数，文章详细展示了整个转换过程，并通过gdb调试工具验证了转换的正确性。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

gdb调试

root@ubuntu:/media/mtk6795/alps/sunwave_pub# gcc -g test.c 
root@ubuntu:/media/mtk6795/alps/sunwave_pub# gdb ./a.out 
GNU gdb (Ubuntu/Linaro 7.4-2012.04-0ubuntu2.1) 7.4-2012.04
Copyright (C) 2012 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.  Type "show copying"
and "show warranty" for details.
This GDB was configured as "x86_64-linux-gnu".
For bug reporting instructions, please see:
<http://bugs.launchpad.net/gdb-linaro/>...
Reading symbols from /media/mtk6795/alps/sunwave_pub/a.out...done.
(gdb) start
Temporary breakpoint 1 at 0x40054c: file test.c, line 6.
Starting program: /media/mtk6795/alps/sunwave_pub/a.out 

Temporary breakpoint 1, main () at test.c:6
6		int a =257; 
(gdb) n
7		int a0=0,a1=0;
(gdb) 
8		unsigned char * pBuf = NULL ;
(gdb) 
9		int b=0;
(gdb) 
10		pBuf = (unsigned char*) malloc(72*128*sizeof(unsigned char));
(gdb) 
13	    pBuf[0] =(unsigned char)(a & 0xff);
(gdb) 
14		pBuf[1] = (unsigned char)((a & 0xff00) >> 8);
(gdb) 
16	    a0 = a%256;
(gdb) 
17	    a1 = a/256;
(gdb) 
19		printf("bruce int2byte  ==>> pBuf[0]=%d,pBuf[1]=%d\n",pBuf[0],pBuf[1]);
(gdb) 
bruce int2byte  ==>> pBuf[0]=1,pBuf[1]=1
20		printf("bruce int2byte  ==>> a0=%d,a1=%d\n",a0,a1);
(gdb) 
bruce int2byte  ==>> a0=1,a1=1
23		b =(int)(( pBuf[0] & 0xff )|((pBuf[1] & 0xff)<<8));
(gdb) 
24		printf("bruce byte2int  ==>> b=%d\n",b);
(gdb) 
bruce byte2int  ==>> b=257
27		return 0;
(gdb) 
28	}
(gdb)

c语言 int与byte[]互相转换

#include<stdio.h>
#include<string.h>
#include<math.h> 
#include<stdlib.h>
int main(){
	int a =257; 
	int a0=0,a1=0;
	unsigned char * pBuf = NULL ;
	int b=0;
	pBuf = (unsigned char*) malloc(72*128*sizeof(unsigned char));

	//int2byte
    pBuf[0] =(unsigned char)(a & 0xff);
	pBuf[1] = (unsigned char)((a & 0xff00) >> 8);

    a0 = a%256;
    a1 = a/256;

	printf("bruce int2byte  ==>> pBuf[0]=%d,pBuf[1]=%d\n",pBuf[0],pBuf[1]);
	printf("bruce int2byte  ==>> a0=%d,a1=%d\n",a0,a1);

    //byte2int
	b =(int)(( pBuf[0] & 0xff )|((pBuf[1] & 0xff)<<8));
	printf("bruce byte2int  ==>> b=%d\n",b);


	return 0;
}