package test;
import java.util.Arrays;
public class MergeSorter {
private int[] sort(int[] in1, int[] in2) {
int[] out = new int[in1.length + in2.length];
int i = 0, j = 0, k = 0;
while (i < in1.length && j < in2.length) {
if (in1[i] <= in2[j]) {
out[k++] = in1[i++];
} else {
out[k++] = in2[j++];
}
}
for (int t1 = i; t1 < in1.length; t1++) {
out[k++] = in1[t1];
}
for (int t2 = j; t2 < in2.length; t2++) {
out[k++] = in2[t2];
}
return out;
}
private int[][] merge(int[][] input) {
int len = (int) Math.ceil(input.length / 2.0);
int[][] output = new int[len][];
int k = 0;
for (int i = 0; i < input.length; i+=2) {
if (i == input.length - 1) {
output[k++] = input[i];
} else {
output[k++] = sort(input[i], input[i+1]);
}
}
return output;
}
public int[] sort(int[] input) {
int[][] mergeArray = new int[input.length][];
for (int i = 0; i < input.length; i++) {
int[] arr = {input[i]};
mergeArray[i] = arr;
}
while (mergeArray.length > 1) {
mergeArray = merge(mergeArray);
}
return mergeArray[0];
}
/**
* @param args
*/
public static void main(String[] args) {
int[] sample = {6, 202, 100, 301, 38, 8, 1, 98, 2, 13, 24, 45};
MergeSorter tester = new MergeSorter();
int res[] = tester.sort(sample);
System.out.println(Arrays.toString(res));
}
}
Java归并排序
最新推荐文章于 2022-05-26 15:48:11 发布
本文介绍了一种基于归并排序算法的实现方式。通过将输入数组拆分成单个元素,再逐步合并相邻的已排序数组来完成整个排序过程。文章包含完整的Java代码示例,并在主函数中演示了如何对一个整数数组进行排序。
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