根据字典的值大小对字典进行排序

一：

In [76]: d = {x:random.randint(60,100) for x in 'abcdefg'}

In [86]: l=list(zip(d.values(),d.keys()))
In [87]: l=sorted(l)#从小到大排列

二：

In [97]: d.items()
Out[97]: dict_items([('a', 80), ('b', 90), ('c', 87), ('d', 70), ('e', 79), ('f', 97), ('g', 92)])


In [98]: sorted(d.items(),key=lambda x:x[1])
Out[98]: [('d', 70), ('e', 79), ('a', 80), ('c', 87), ('b', 90), ('g', 92), ('f', 97)]