小型项目程序 ERP——沙盘模拟

最新推荐文章于 2025-07-26 03:33:31 发布

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最新推荐文章于 2025-07-26 03:33:31 发布 · 1.3k 阅读

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#应用

第一次做一个小型的应用程序，初涉这一方面（室友还以为我做不出来，差距还差的远呢）

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
using namespace std;
int yearpay,seasonpay;
int sum=70;
int timep1=0,timep2=0,timep3=0,timep4=0;
int timec1=0,timec2=0,timec3=0,timec4=0,timec5=0;
int timei1=0,timei2=0;
int timeo1=0,timeo2=0,timeo3=0,timeo4=0;
int o2[15],o3[15],o4[15];
int r1[15][5],r2[15][5],r3[15][5],r4[15][5];
int ip2=0,ip3=0,ip4=0;
int ma[5][5],m1[5][5],m2[5][5],m3[5][5],m4[5][5];
void loanmoney(int a)
{
    double loansum,loansum1,loanyear; //贷款
    if(a==1)
    {
        int  flag;
        cout<<"是否进行长贷(1:是 0:否)   ";
        cin>>flag;
        if(flag==1)
        {
            cout<<"输入您要长期贷款的数目和年限  "<<endl;
            cin>>loansum>>loanyear;
            sum+=loansum;
            printf("您需要每一年还款利息%lf\n",round(loansum*0.1));
        }
        cout<<"是否进行短贷(1:是 0:否)   ";
        cin>>flag;
        if(flag==1)
        {
            cout<<"输入您要短期贷款的数目";
            cin>>loansum;
            sum+=loansum;
            printf("您需要还款利息%lf\n",round(loansum*0.05));
        }
    }
    else
    {
        int flag;
        cout<<"是否进行短贷(1:是 0:否)   ";
        cin>>flag;
        if(flag==1)
        {
            cout<<"输入您要短期贷款的数目";
            cin>>loansum;
            sum+=loansum;
            printf("您需要还款利息%lf",round(loansum*0.05));
        }
    }
    cout<<"******剩余总额"<<sum<<endl;
    cout<<"******贷款结束********"<<endl;
    cout<<"*******************************"<<endl;
}
void setroom()
{
    //大小厂房
    double bigroom,smallroom,roomyear1,roomyear2;
    int flag,isize,numchang1,numchang2,room=0;
    cout<<"厂房租or买(1为买 0为租 -1为租和买 2为不买不粗)";
    cin>>flag;
    if(flag==0||flag==-1)
    {

        cout<<"厂房租用的年限 个数(先大后小)";
        cin>>roomyear1>>numchang1>>roomyear2>>numchang2;
        cout<<"租厂房的花费:";
        cout<<4*roomyear1+3*roomyear2;
        cout<<endl;
        seasonpay+=4*roomyear1+3*roomyear2;
        sum-=4*roomyear1+3*roomyear2;
        room=room+numchang1*6+numchang2*4;

    }
    if(flag==1||flag==-1)
    {
        cout<<"厂房购买的个数(先大后小)";
        cin>>numchang1>>numchang2;
        cout<<"买厂房的花费:";
        cout<<numchang1*40+numchang2*30;
        seasonpay+=numchang1*40+numchang2*30;
        room=room+numchang1*6+numchang2*4;
        sum-=numchang1*40+numchang2*30;
    }
    cout<<"厂房容量:"<<room<<endl;
    cout<<"********剩余总额"<<sum<<endl;
    cout<<"********厂房结束********"<<endl;
    cout<<"*******************************"<<endl;
}
void setproduction()
{
    int sum1,sum2,sum3;
    int cntpro1,cntpro2,cntpro3,cntpro4,sumpro,cntpro;
    cout<<"(1为手工  2为半自动  3为全自动   4为柔性1)"<<endl;
    cout<<"购置费   生产周期  总转产费  转产周期   维修费  残值"<<endl;
    cout<<"1: 5M       3Q        0M       无       1M/Y    1M " <<endl;
    cout<<"2: 10M      2Q        1M       1Q       1M/Y    2M " <<endl;
    cout<<"3: 15M      1Q        2M       1Q       1M/Y    3M "<<endl;
    cout<<"4: 20M      1Q        0M       无       1M/Y    4M "<<endl;
    cout<<"输入各种生产线的数量"<<endl;
    cin>>cntpro1>>cntpro2>>cntpro3>>cntpro4;
    cntpro=cntpro1+cntpro2+cntpro3+cntpro4;
    for(int i=ip2+1; i<=cntpro2+ip2; i++)
        o2[i]++;
    for(int i=ip3+1; i<=cntpro3+ip3; i++)
        o3[i]++;
    for(int i=ip4+1; i<=cntpro4+ip4; i++)
        o4[i]++;
    ip2+=