递归列表项, 生成新的列表
;; wages
(define (wages hours)
(* 12 hours)
)
;; hours->wages list-of-number -> list-of-number
;; 计算周工资表
(define( hours-wages a-list-of-week-hours )
(cond
[(empty? a-list-of-week-hours) empty]
[else (cons (wages (first a-list-of-week-hours)) (hours-wages (rest a-list-of-week-hours)) ) ]
)
)