1001. A+B Format (20)

最新推荐文章于 2022-05-24 08:47:14 发布

转载最新推荐文章于 2022-05-24 08:47:14 发布 · 208 阅读

本文介绍了一个简单的C++程序，该程序接收两个整数作为输入，并以标准格式输出它们的和，即每三位数字用逗号分隔。程序考虑了不同范围的整数输入，并提供了相应的格式化输出。

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

#include<iostream>
#include<math.h>
using namespace std;
int main (){
int a,b,sum,i,j,k;
cin>>a>>b;
sum=a+b;

i=sum/1000000;
j=(sum%1000000)/1000;
k=(sum%1000);

if(abs(sum)<1000){
cout<<k<<endl;
}
if(abs(sum)>999&&abs(sum)<1000000){
printf("%d,%03d\n",j,abs(k));
}
if(abs(sum)>999999){
printf("%d,%03d,%03d\n",i,abs(j),abs(k));
}

return 0;
}