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本文介绍了一种基于玛雅历法的日期转换算法，通过输入玛雅历法中的Haab和Tzolkin历法的日期，可以计算出对应的现代日期。算法使用C语言实现，包括了对临界点的特殊处理，确保了计算的准确性。

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~题目链接~

http://poj.org/problem?id=1008&lang=default&change=true

输入

3
10. zac 0
0. pop 0
10. zac 1995

结果

3
3 chuen 0
1 imix 0
9 cimi 2801

注意处理临界点

4. uayet 259
正解是 13 ahau 364
而不是13 ahau 365

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

char Haab[19][10]= {"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax","zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"};
char Tzolkin[20][10]= {"imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk","ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac","ahau"};

int main()
{
    int n;
    scanf("%d",&n);
    printf("%d\n",n);
    while(n--)
    {
        int day,year,data=0,i;
        char s[10];
        scanf("%d%*c%*c%s%*c%d",&day,s,&year);
        for(i=0; i<19; i++)
            if(strcmp(s,Haab[i])==0)
                //data=365*year+20*i+day;
                data=365*year+20*i+day+1;//总计天数
        //year=data/260;
        year=(data-1+260)/260-1;//年份（注意这组数据：4. uayet 259）
        //day=data%13;
        day=(data-1+13)%13+1;//日期计算（注意每一年的Tzolkin历最后一天）
        //int month=data%20;
        int month=(data-1+20)%20+1;
        //printf("%d %s %d\n",day+1,Tzolkin[month],year);
        printf("%d %s %d\n",day,Tzolkin[month-1],year);
    }

    return 0;
}

转载于:https://www.cnblogs.com/guoyongzhi/p/3233049.html