Total Accepted: 46246
Total Submissions: 104863
Difficulty: Easy
Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.
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void deleteNode(ListNode* node) {
if(node->next == NULL)
{
node = NULL;
return ;
}
node->val = node->next->val;
node->next = node->next->next;
}
本文介绍了一种在单链表中删除指定节点的方法,不使用头指针的情况下仅通过给定节点来操作。
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