POST 提交XML 文件

最新推荐文章于 2025-04-21 17:16:52 发布

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最新推荐文章于 2025-04-21 17:16:52 发布

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分类专栏： WEB JAVA

本文链接：https://blog.youkuaiyun.com/dailuwen/article/details/52103398

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本文提供了一个使用Java实现HTTP请求与响应中XML数据交互的例子。包括发送POST请求并附带XML格式的数据，以及如何从HTTP请求中读取并打印XML数据。

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1、请求

import static org.junit.Assert.assertTrue;

import java.io.IOException;

import org.apache.commons.io.IOUtils;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.HttpClientBuilder;
import org.apache.http.protocol.HTTP;
import org.apache.http.util.EntityUtils;
import org.junit.Before;
import org.junit.Test;
import org.springframework.core.io.ClassPathResource;


public class ctrlDemo {

    private HttpClient httpClient;

    @Before
    public void setUp() {
        httpClient = HttpClientBuilder.create().build();
    }

    @Test
    public void test() throws Exception {
        String url = "http://";

        String xml = loadData("***.xml");

        BaseResp baseReqsp = executePost(url, xml, httpClient);
        assertTrue(baseReqsp.isSuccess());
    }

    private String loadData(String path) throws IOException {
        ClassPathResource resource = new ClassPathResource(path);
        return IOUtils.toString(resource.getInputStream());
    }
    
    public static void executePost(String url, String body, HttpClient httpClient) throws Exception{
        HttpPost httpPost = new HttpPost(url);
        httpPost.addHeader(HTTP.CONTENT_TYPE, "application/xml");//请求参数为XML格式 
        
        StringEntity entity = new StringEntity(body, "UTF-8");  
        httpPost.setEntity(entity);  
        HttpResponse resp = httpClient.execute(httpPost);
        HttpEntity respEntity = resp.getEntity();
        String text = EntityUtils.toString(respEntity, "UTF-8");
    }

}

2、接收

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import org.apache.commons.io.IOUtils;

	@RequestMapping(value = "/xml/请求路径", method = RequestMethod.POST)
    public void order(HttpServletRequest request, HttpServletResponse response) {
        
            String xmlReq = IOUtils.toString(request.getInputStream());
            System.out.println("data: {}", xmlReq);

			// unmarshal : 使用 JAXB 解析 (具体如何解析请看 http://www.oschina.net/question/tag/jaxb )
			//Object : 代表需要解析的JAVA类
            Object data = unmarshal(xmlReq, Object.class, false);
            

    }