android双后台服务，消息通知类(service2)

最新推荐文章于 2024-04-24 14:06:43 发布

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本文介绍了一个名为Service2的Android服务示例，该服务能够启动另一个服务Service1，并在设备上显示通知。Service2还包含了一些生命周期回调方法的实现。

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package com.service.demo;

import java.util.List;

import android.app.ActivityManager;
import android.app.ActivityManager.RunningAppProcessInfo;
import android.app.ActivityManager.RunningServiceInfo;
import android.app.Application;
import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.app.Service;
import android.content.Context;
import android.content.Intent;
import android.os.Handler;
import android.os.IBinder;
import android.os.RemoteException;
import android.support.v4.app.NotificationCompat;
import android.util.Log;
import android.widget.Toast;
/**
*
* @author 掌缘生灭
*
*/
public class Service2 extends Service {
private String TAG = getClass().getName();
private String Process_Name = "com.example.servicetest2:service1";

/**
*启动Service1
*/
private StrongService startS1 = new StrongService.Stub() {

@Override
public void stopService() throws RemoteException {
Intent i = new Intent(getBaseContext(), Service1.class);
getBaseContext().stopService(i);
}

@Override
public void startService() throws RemoteException {
Intent i = new Intent(getBaseContext(), Service1.class);
getBaseContext().startService(i);

}
};

@Override
public void onTrimMemory(int level){
Toast.makeText(getBaseContext(), "Service2 onTrimMemory..."+level, Toast.LENGTH_SHORT)
.show();
keepService1();
}

public void onCreate() {
Toast.makeText(Service2.this, "Service2 onCreate...", Toast.LENGTH_SHORT).show();
keepService1();

new Thread()
{
int i=0;
public void run()
{
while(true)
{

ServiceUtils.showNotification(Service2.this,"测试标题","测试内容","1234");
try
{
Thread.sleep(5000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}

}
}.start();
}

/**
* @获取默认的pendingIntent,为了防止2.3及以下版本报错
* @flags属性:
* 在顶部常驻:Notification.FLAG_ONGOING_EVENT
* 点击去除： Notification.FLAG_AUTO_CANCEL
*/
public PendingIntent getDefalutIntent(int flags){
PendingIntent pendingIntent= PendingIntent.getActivity(this, 1, new Intent(), flags);
return pendingIntent;
}

/**
* 判断Service1是否还在运行，如果不是则启动Service1
*/
private void keepService1(){
boolean isRun = ServiceUtils.isProessRunning(Service2.this, Process_Name);
if (isRun == false) {
try {
Toast.makeText(getBaseContext(), "重新启动 Service1", Toast.LENGTH_SHORT).show();
startS1.startService();
} catch (RemoteException e) {
e.printStackTrace();
}
}
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
return START_STICKY;
}

@Override
public IBinder onBind(Intent intent) {
return (IBinder) startS1;
}

}