获取Ubuntu Linux上的前10个文件或目录

Ubuntu Linux has a rich set of commands for manipulating and accessing files. The du utility gives information on disk usage, and the sort utility can sort the results. Finally, we can run those results through the head command, which gives you the top 10 lines outputted through any other command. We’ll chain the commands together to get the output that we want.

Ubuntu Linux有一组丰富的用于操作和访问文件的命令。 du实用程序提供有关磁盘使用情况的信息，sort实用程序可以对结果进行排序。 最后，我们可以通过head命令运行这些结果，该命令为您提供通过任何其他命令输出的前10行。 我们将命令链接在一起以获得所需的输出。

First we’ll use the du -sm command to give the results in MB:

首先，我们将使用du -sm命令以MB为单位给出结果：

$ du -sm *1 wp-config-sample.php1 wp-config.php14 wp-content1 wp-feed.php—- trimmed —

$ du -sm * 1 wp-config-sample.php1 wp-config.php14 wp-content1 wp-feed.php —修剪—

Now we can see that the results aren’t sorted, so we’ll sort them by the sort -nr command, which sorts by numerical value in reverse. Finally, we’ll run the results through head -10 to get the top 10 results:

现在我们可以看到结果没有排序，因此我们将通过sort -nr命令对其进行排序，该命令将按相反的数值进行排序。 最后，我们将结果从头-10开始进行计算以获得前十个结果：

This is the command we are going to run:

这是我们要运行的命令：

du -sm * | sort -nr | head -10

du -sm * | 排序-nr | 头-10

Here’s an example of the output:

这是输出示例：

$ du -sm * | sort -nr | head -1014 wp-content2 wp-includes1 xmlrpc.php1 xml.php1 x.php1 wp-trackback.php1 wp-settings.php1 wp-rss2.php1 wp-rss.php1 wp-register.php

$ du -sm * | 排序-nr | 头-1014 wp-content2 wp-includes1 xmlrpc.php1 xml.php1 x.php1 wp-trackback.php1 wp-settings.php1 wp-rss2.php1 wp-rss.php1 wp-register.php

Useful stuff.

有用的东西。

翻译自: https://www.howtogeek.com/howto/ubuntu/get-the-top-10-files-or-directories-on-ubuntu-linux/