Restore standby database controlfile in ASM (refreshing standby controlfile)

If your standby database uses ASM and you need to refresh the standby controlfile, how do you do this? How do you get the new standby controlfile into ASM?

We use RMAN for this.

First you need to create a new standby controlfile on the primary database using the command:
SQL>alter database create standby controlfile as '/usr/tmp/X.dbvisit.20010.dbvrac1.standbycontrolfile.ctl' reuse;

This file (/usr/tmp/X.dbvisit.20010.dbvrac1.standbycontrolfile.ctl) is then copied to the standby server.

On the standby server start the standby database in nomount mode:
[oracle@dbvrac1 tmp]$ sqlplus "/ as sysdba"

SQL*Plus: Release 10.2.0.1.0 - Production on Wed Jul 29 21:39:29 2009

Copyright (c) 1982, 2005, Oracle. All rights reserved.

Connected to an idle instance.

SQL> startup nomount
ORACLE instance started.

Total System Global Area 335544320 bytes
Fixed Size 1219280 bytes
Variable Size 109053232 bytes
Database Buffers 222298112 bytes
Redo Buffers 2973696 bytes
SQL> exit
Disconnected from Oracle Database 10g Release 10.2.0.1.0 - Production
With the Real Application Clusters option


Then start RMAN and restore the standby controlfile from the file system into ASM. In this case there are 2 controlfiles:
[oracle@dbvrac1 tmp]$ rman

Recovery Manager: Release 10.2.0.1.0 - Production on Wed Jul 29 21:41:20 2009

Copyright (c) 1982, 2005, Oracle. All rights reserved.

RMAN> connect target

connected to target database: dbvrac (not mounted)

RMAN> restore controlfile to '+DATA/DBVRAC/controlfile/Current.256.645671167' from '/usr/tmp/X.dbvisit.20010.dbvrac1.standbycontrolfile.ctl';

Starting restore at 29-JUL-09
using target database control file instead of recovery catalog
allocated channel: ORA_DISK_1
channel ORA_DISK_1: sid=147 instance=dbvrac1 devtype=DISK

channel ORA_DISK_1: copied control file copy
Finished restore at 29-JUL-09

RMAN> restore controlfile to '+DATA/DBVRAC/controlfile/Current.257.645671169' from '/usr/tmp/X.dbvisit.20010.dbvrac1.standbycontrolfile.ctl';

Starting restore at 29-JUL-09
using channel ORA_DISK_1

channel ORA_DISK_1: copied control file copy
Finished restore at 29-JUL-09

RMAN>

Completed. The standby controlfiles have been refreshed and the standby database can be used again.

come from:http://www.dbvisit.com/forums/showthread.php?p=445

来自 “ ITPUB博客 ” ,链接:http://blog.itpub.net/90618/viewspace-710449/,如需转载,请注明出处,否则将追究法律责任。

转载于:http://blog.itpub.net/90618/viewspace-710449/

资源下载链接为: https://pan.quark.cn/s/f989b9092fc5 今天给大家分享一个关于C#自定义字符串替换方法的实例,希望能对大家有所帮助。具体介绍如下: 之前我遇到了一个算法题,题目要求将一个字符串中的某些片段替换为指定的新字符串片段。例如,对于源字符串“abcdeabcdfbcdefg”,需要将其中的“cde”替换为“12345”,最终得到的结果字符串是“ab12345abcdfb12345fg”,即从“abcdeabcdfbcdefg”变为“ab12345abcdfb12345fg”。 经过分析,我发现不能直接使用C#自带的string.Replace方法来实现这个功能。于是,我决定自定义一个方法来完成这个任务。这个方法的参数包括:原始字符串originalString、需要被替换的字符串片段strToBeReplaced以及用于替换的新字符串片段newString。 在实现过程中,我首先遍历原始字符串,查找需要被替换的字符串片段strToBeReplaced出现的位置。找到后,就将其替换为新字符串片段newString。需要注意的是,在替换过程中,要确保替换操作不会影响后续的查找和替换,避免遗漏或重复替换的情况发生。 以下是实现代码的大概逻辑: 初始化一个空的字符串result,用于存储最终替换后的结果。 使用IndexOf方法在原始字符串中查找strToBeReplaced的位置。 如果找到了,就将originalString中从开头到strToBeReplaced出现位置之前的部分,以及newString拼接到result中,然后将originalString的查找范围更新为strToBeReplaced之后的部分。 如果没有找到,就直接将剩余的originalString拼接到result中。 重复上述步骤,直到originalStr
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