【LeetCode.134】Gas Station(加油站 | medium)

There are N gas stations along a circular route, where the amount of gas at station i is gas[i].

You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.

Return the starting gas station's index if you can travel around the circuit once in the clockwise direction, otherwise return -1.

Note:

If there exists a solution, it is guaranteed to be unique.
Both input arrays are non-empty and have the same length.
Each element in the input arrays is a non-negative integer.

来源:力扣(LeetCode)
链接:https://leetcode-cn.com/problems/gas-station
著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。

public class LeetCode134 {

    public int canCompleteCircuit(int[] gas, int[] cost){
        int start = 0, run = 0, rest = 0;
        for(int i = 0; i < gas.length; i ++){
            run += (gas[i] - cost[i]);
            rest += (gas[i] - cost[i]);
            if(run < 0){
                start = i + 1;
                run = 0;
            }
        }
        return rest < 0 ? -1 : start;
    }

    public static void main(String[] args) {
        int[] gas = new int[]{1,2,3,4,5};
        int[] cost = new int[]{3,4,5,1,2};
        LeetCode134 l = new LeetCode134();
        System.out.println(l.canCompleteCircuit(gas, cost));
    }
}

 

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值