单链表是笔试以及面试手写代码中常考的数据结构之一。下面实现了单链表的常见操作:创建单链表、删除节点、打印单链表(包括正向打印以及逆向打印)、反转单链表、找出单链表的倒数第K个节点、合并两个有序单链表等操作。
代码(C++):
- //笔试面试单链表常用操作编程实现
- #include <iostream>
- #include <stack>
- #include <cstdlib>
- using namespace std;
- //单链表节点数据结构定义
- typedef struct link_node_s{
- int m_val;
- struct link_node_s *next;
- }link_node_t,*link_list_t;
- //函数:创建单链表(头插法)
- link_list_t create_linklist(int *a,int n);
- //函数:打印单链表(从头到尾)
- void print_linklist(link_list_t head);
- //函数:打印单链表(从尾到头)
- void print_linklist_reverse(link_list_t head);
- //函数:新建链表节点
- link_list_t creart_linknode(int val);
- //函数:删除链表中的某一个节点(前提条件:该节点一定存在)
- //性能要求:在O(1)时间复杂度内实现
- void delete_node_exist(link_list_t *head,link_list_t node_deleted);
- //函数:删除链表中数据值等于给定值的节点
- void delete_node(link_list_t *head,int val);
- //函数:获得链表中的倒数第K个节点
- link_list_t get_kth_node(link_list_t head,int k);
- //函数:反转链表
- link_list_t reverse_linklist(link_list_t head);
- //函数:合并两个已排序的链表(递归方法实现)
- link_list_t merge_linklist_recursive(link_list_t head1,link_list_t head2);
- int main(){
- const int num1 = 8;
- const int num2 = 10;
- int *a = new int[num1];
- int *b = new int[num2];
- int *a_sorted = new int[num1];
- int *b_sorted = new int[num2];
- srand(1);
- for(int i = 0;i < num1;++i){
- *(a + i) = rand() % 100;
- *(a_sorted + i) = 50 - i * 2 + 8;
- }
- for(int i = 0;i < num2;++i){
- *(b + i) = rand() % 200;
- *(b_sorted + i) = 50 - i * 4 + 1;
- }
- cout << "**********创建链表测试**********" << endl;
- link_list_t list1 = create_linklist(a,num1);
- link_list_t list2 = create_linklist(b,num2);
- link_list_t list_sorted1 = create_linklist(a_sorted,num1);
- link_list_t list_sorted2 = create_linklist(b_sorted,num2);
- cout << "**********输出链表测试(正向输出)**********" << endl;
- cout << "链表1:" << endl;
- print_linklist(list1);
- cout << "链表1(已序):" << endl;
- print_linklist(list_sorted1);
- cout << "链表2(已序):" << endl;
- print_linklist(list_sorted2);
- cout << "**********输出链表测试(逆向输出)**********" << endl;
- print_linklist_reverse(list1);
- cout << "**********获取链表的倒数第K个节点测试**********" << endl;
- int k = 3;
- link_list_t kth_node = get_kth_node(list1,k);
- if(NULL == kth_node)
- cout << "链表中倒数第" << k << "个节点不存在" << endl;
- else
- cout << "链表中倒数第" << k <<"个节点是: " <<kth_node->m_val << endl;
- k = 8;
- kth_node = get_kth_node(list1,k);
- if(NULL == kth_node)
- cout << "链表中倒数第" << k << "个节点不存在" << endl;
- else
- cout << "链表中倒数第" << k <<"个节点是: " <<kth_node->m_val << endl;
- k = 11;
- kth_node = get_kth_node(list1,k);
- if(NULL == kth_node)
- cout << "链表中倒数第" << k << "个节点不存在" << endl;
- else
- cout << "链表中倒数第" << k <<"个节点是: " <<kth_node->m_val << endl;
- cout << "**********删除链表中一定存在的节点测试(输入参数是要删除的节点指针)**********" << endl;
- link_list_t node_deleted = list1;
- while(node_deleted->m_val != *(a + 4))
- node_deleted = node_deleted->next;
- cout << "删除节点" << *(a + 4) << "之后的单链表:" << endl;
- delete_node_exist(&list1,node_deleted);
- print_linklist(list1);
- node_deleted = list1;
- while(node_deleted->m_val != *(a + 6))
- node_deleted = node_deleted->next;
- cout << "删除节点" << *(a + 6) << "之后的单链表:" << endl;
- delete_node_exist(&list1,node_deleted);
- print_linklist(list1);
- cout << "**********删除链表中值等于给定值的节点测试(不一定存在,输入参数是int型值)**********" << endl;
- const int val_deleted = 22;
- delete_node(&list1,val_deleted);
- cout << "删除值等于" << val_deleted << "之后的链表:" << endl;
- print_linklist(list1);
- cout << "**********合并链表测试**********" << endl;
- link_list_t merge_list_head = merge_linklist_recursive(list_sorted1,list_sorted2);
- print_linklist(merge_list_head);
- cout << "**********逆转链表测试**********" << endl;
- link_list_t head_reverse = reverse_linklist(<span style="font-family: Arial, Helvetica, sans-serif;">merge_list_head</span><span style="font-family: Arial, Helvetica, sans-serif;">);</span>
- cout << "逆转之后的链表:" << endl;
- cout << "头节点:" << head_reverse->m_val << endl;
- print_linklist(head_reverse);
- return 0;
- }
- //函数:创建单链表(头插法)
- link_list_t create_linklist(int *a,int n){
- link_list_t head = NULL;
- if(NULL == a || 0 == n)
- return NULL;
- for(int i = 0;i < n;++i){
- link_list_t new_node = creart_linknode(*(a + i));
- if(NULL == head){
- head = new_node;
- }
- else{
- new_node->next = head;
- head = new_node;
- }
- }
- return head;
- }
- //函数:新建链表节点
- link_list_t creart_linknode(int val){
- link_list_t node = new link_node_t;
- node->m_val = val;
- node->next = NULL;
- return node;
- }
- //函数:打印单链表
- void print_linklist(link_list_t head){
- link_list_t node = head;
- cout << "正向输出单链表" << endl;
- while(node != NULL){
- cout << node->m_val << " ";
- node = node->next;
- }
- cout << endl;
- return;
- }
- //函数:打印单链表(从尾到头)
- void print_linklist_reverse(link_list_t head){
- stack<int> node_stack;
- link_list_t node = head;
- while(node != NULL){
- node_stack.push(node->m_val);
- node = node->next;
- }
- cout << "逆向输出单链表" << endl;
- while(!node_stack.empty()){
- cout << node_stack.top() << " ";
- node_stack.pop();
- }
- cout << endl;
- return;
- }
- //函数:删除链表中的某一个节点(前提条件:该节点一定存在)
- //性能要求:在O(1)时间复杂度内实现
- void delete_node_exist(link_list_t *head,link_list_t node_deleted){
- //算法思想:
- //通过拷贝要删除节点的后继节点的内容覆盖要删除节点的内容,然后删除要删除节点的后继节点即可
- //要考虑的特殊情况是:要删除的节点是链表尾部节点,仍然需要遍历链表
- if(NULL == head || NULL == node_deleted)
- return;
- //要删除的节点不是尾节点
- if(node_deleted->next != NULL){
- link_list_t next_node = node_deleted->next;
- node_deleted->m_val = next_node->m_val;
- node_deleted->next = next_node->next;
- delete next_node;
- next_node = NULL;
- }
- //链表中只有一个节点
- else if(*head == node_deleted){
- delete node_deleted;
- node_deleted = NULL;
- *head = NULL;
- }
- //要删除的节点是尾节点
- else{
- link_list_t node = *head;
- while(node->next != node_deleted)
- node = node->next;
- node->next = node_deleted->next;
- delete node_deleted;
- node_deleted = NULL;
- }
- return;
- }
- //函数:获得链表中的倒数第K个节点
- link_list_t get_kth_node(link_list_t head,int k){
- //性能:只需遍历链表一遍即可
- //算法思想:设置两个指针,一个指向链表头部,一个指向第k个节点,然后两个指针同时向后移动,当第二个指针指向链表的尾节点时,第一个指针指向的节点便是倒数第K个节点
- //注意代码的鲁棒性,防止程序的崩溃
- if(NULL == head || k <= 0)
- return NULL;
- //设置两个指针
- link_list_t p1 = head,p2 = head;
- int i = 0;
- //第二个指针向前走k-1步
- while(i < k - 1 && p2->next != NULL){
- p2 = p2->next;
- ++i;
- }
- //注意链表中总节点数小于K的情况
- if(i != k - 1 && NULL == p2->next)
- return NULL;
- //两个指针同时向后前进
- while(p2->next != NULL){
- p1 = p1->next;
- p2 = p2->next;
- }
- return p1;
- }
- //函数:反转链表
- //返回值:反转之后的链表头节点
- link_list_t reverse_linklist(link_list_t head){
- //链表为空或者只有一个节点
- if(NULL == head || NULL == head->next)
- return head;
- link_list_t prev_node = NULL,next_node,cur_node = head,head_reverse;
- while(cur_node != NULL){
- next_node = cur_node->next;
- if(NULL == next_node)
- head_reverse = cur_node;//原链表尾节点即逆转后链表的头节点
- cur_node->next = prev_node;
- prev_node = cur_node;
- cur_node = next_node;
- }
- return head_reverse;
- }
- //函数:删除链表中数据值等于给定值的节点
- void delete_node(link_list_t *head,int val){
- if(NULL == head){
- cout << "Delete node failed :The node to be delete not exist!" << endl;
- return;
- }
- if(val == (*head)->m_val){
- link_list_t node = *head;
- *head = (*head)->next;
- delete node;
- return;
- }
- //首先判断该节点是否存在链表中
- link_list_t node = *head;
- while(node->next != NULL){
- if(val == node->next->m_val)
- break;
- node = node->next;
- }
- //存在满足条件的节点
- if(node->next != NULL){
- link_list_t node_delete = node->next;
- node->next = node_delete->next;
- delete node_delete;
- }
- else
- cout << "删除失败:链表中不存在值等于" << val << "的节点" << endl;
- return;
- }
- //函数:合并两个已排序的链表(递归方法实现)
- link_list_t merge_linklist_recursive(link_list_t head1,link_list_t head2){
- if(NULL == head1)
- return head2;
- else if(NULL == head2)
- return head1;
- link_list_t merge_head = NULL;
- if(head1->m_val < head2->m_val){
- merge_head = head1;
- merge_head->next = merge_linklist_recursive(head1->next,head2);
- }
- else{
- merge_head = head2;
- merge_head->next = merge_linklist_recursive(head1,head2->next);
- }
- return merge_head;
- }
测试平台:WIn8+Ubuntu12.04+Vim+G++:
运行结果:
本文转载自优快云博客博主江南烟雨原创文章,博客原文地址:http://blog.youkuaiyun.com/xiajun07061225/article/details/9246573