在字符串中计算字符出现的次数

#include <stdio.h>
int main ()
{
    char arr[] = {"Hello # 1234"};
    char count[256] = {0}; //初始化
    char *t = arr;
    while(*t)
    {
        count[*t]++;
        t++;
    } //将arr的元素给count   

    int i = 0;
    for(i = 0; i < 256; i++)
    {
        if(brr[i]) //如果brr[i]存在，就输出
        {
            printf("%c count %d\n", i, count[i]);
        }
    return 0;
    }
}