tomcat的websocket注入空白报错调用不了service

最新推荐文章于 2023-06-08 21:43:58 发布

原创最新推荐文章于 2023-06-08 21:43:58 发布 · 456 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#java #spring #servlet

文章描述了一个使用Springboot构建的WebSocket服务端组件，其中在WebSocketServer类中定义了一个静态的ApplicationContext。在应用启动时，通过SpringApplication.run方法获取到ApplicationContext并赋值给WebSocketServer。当需要发送消息时，从ApplicationContext中获取相关服务实例，如ExpService、ExpRecordService等，以便进行服务器主动推送。

1.在websocketService里面定义一个静态ApplicationContext；

@ServerEndpoint("/imserver/{userId}")
@Component
public class WebSocketServer {

    private static ApplicationContext applicationContext;

    public static void setApplicationContext(ApplicationContext context){
        applicationContext = context;
    }
    //下面这些都是外部引用的service
	private ExpService expService;

    private ExpRecordService expRecordService;

    private ExpRegistrationService expRegistrationService;
    ...
}

2.在Springboot的启动器Application的main方法里面，去接收该context并赋值给上文的applicationContext

@SpringBootApplication
public class EvaluateApplication extends SpringBootServletInitializer {

    public static void main(String[] args) {
        ConfigurableApplicationContext context = SpringApplication.run(EvaluateApplication.class, args);
        WebSocketServer.setApplicationContext(context);
    }

}

3.在sendMessage方法里面给这些service赋值

/**
     * 实现服务器主动推送
     */
    public void sendMessage(String message) throws IOException {
        expRegistrationService = (ExpRegistrationService)applicationContext.getBean(ExpRegistrationService.class);
        expRecordService = (ExpRecordService)applicationContext.getBean(ExpRecordService.class);
        expService = (ExpService)applicationContext.getBean(ExpService.class);
        this.session.getBasicRemote().sendText(message);
    }