<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[csdn26618的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/csdn26618</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; csdn26618]]></copyright><item><title><![CDATA[建立个链表，每个结点包括: 学号、姓名、性别、年龄。 输入一个年龄，如果链表中的结点所包含的年龄等于此年龄， 则将此结点删去。(不考虑删除的是表头和表尾节点)]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80159712</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80159712</guid><author>csdn26618</author><pubDate>Tue, 01 May 2018 21:12:28 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;#include &quot;string.h&quot;struct student{ 	int no;//学号	char name[10];//年龄	char sex[10];//性别，男：M(male),女：F(female)	int age;//年龄	struct student *next;};void main(){ 	struct student a,b,c,*hea...]]></description><category></category></item><item><title><![CDATA[求2^x的功能部分，在函数exp中完成。 2^0+(2^0+2^1)+(2^0+2^1+2^2)+…+(2^0+2^1+2^2+…+2^n)]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80156366</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80156366</guid><author>csdn26618</author><pubDate>Tue, 01 May 2018 14:30:20 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;double exp(int m)//用递归调用求(2^n)2的n次方{	if(m==0)		return 1;	else	 	return 2*exp(m-1); }void main(){	int x,i,j;	double sum=0;	printf(&quot;请输入 x 的值：&quot;);	scanf(&quot;%d&quot;,&amp;amp;x);	for(i=0;i&amp;lt;=x;i++...]]></description><category></category></item><item><title><![CDATA[输入学生信息，包括姓名、成绩，按平均分划分等级，大于平均分的为A等级， 与A等级相差10 分以内的为B 等级，其它为C 等级，学生人数不可超过50人。]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80152250</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80152250</guid><author>csdn26618</author><pubDate>Mon, 30 Apr 2018 21:25:17 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;#define  N 10    //N的值&amp;lt;=50struct student{      char name[8];//姓名    float score;//成绩    char rank;//等级} stu[N];void main(){    struct student stu[N];    int i;    float sum=0,avg;...]]></description><category></category></item><item><title><![CDATA[有10个学生,每个学生的数据包括(学号,姓名、3门课程的成绩)， 从键盘输入10个学生数据，要求打印出3门课程平均成绩， 以及最高分的学生数据（包括学号、姓名、3门课程成绩、平均分数）]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80152221</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80152221</guid><author>csdn26618</author><pubDate>Mon, 30 Apr 2018 21:22:59 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;#define N 10struct student{ 	int no;//学号  	char name[8];//姓名    float score[3];//成绩    float avg;//平均成绩} stu[N];void main(){	struct student stu[N];	int i,wz;//位置	double max;//最高分	for...]]></description><category></category></item><item><title><![CDATA[编写一个函数， 输入n为偶数时，调用函数求1/2+1/4+...+1/n, 当输入n 为奇数时，用函数I 1/1+1/3+...+1/n(利用函数指针)]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80146416</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80146416</guid><author>csdn26618</author><pubDate>Sun, 29 Apr 2018 23:06:00 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;double osh(int n)//偶数和{	double sum=0;	int i;    for(i=2;i&amp;lt;=n;i+=2)        sum+=1.0/i;         return sum;	}double jsh(int n)//奇数和{	double sum=0;	int i;    for(i=1;i&amp;lt;=n;i+=2)   ...]]></description><category></category></item><item><title><![CDATA[7.写函数原型为 int strcmp(char *s1,char *s2)的函数， 该函数实现两个字符串的比较。(不用库函数 strcmp,相等为0, 不等结果为第一个不等字符的 ASCII 之差]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80099384</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80099384</guid><author>csdn26618</author><pubDate>Thu, 26 Apr 2018 20:36:53 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;#include &quot;math.h&quot;int strcmp(char *s1,char *s2){   while(*s1!='\0'&amp;amp;&amp;amp; *s1==*s2)   {      s1++;      s2++;   }    	return *s1-*s2 ;	}void main(){	char a[100],b[100];	int num;	pr...]]></description><category></category></item><item><title><![CDATA[编写一个求字符串的函数(参数用指针)，在主函数中输入字符串，并输出其长度]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80031625</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80031625</guid><author>csdn26618</author><pubDate>Sat, 21 Apr 2018 17:26:49 +0800</pubDate><description><![CDATA[/* 字符串长度要小于字符数组的长度，例如：	char str[]=&quot;hello&quot;;	sizof(str)的值为10（数组长度）	strlen(str)的值为5（字符串长度）*/#include &quot;stdio.h&quot;//#include &quot;string.h&quot;int fun(char *a){	int num=0; 	while(*a!='\0')	{		num++;		a++;		}	//num=s...]]></description><category></category></item><item><title><![CDATA[指针实现，对传递过来的两个实型数，计算它们的和与积之后，通过参数返回]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80030342</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80030342</guid><author>csdn26618</author><pubDate>Sat, 21 Apr 2018 15:49:10 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;void fun(int  *x,int  *y){	int m=*x,n=*y;	int sum,product;//和，积	sum=m+n;	product=m*n; 	*x=sum; 	*y=product;}void main(){	 int a,b;	 printf(&quot;请输入2个数a和b：&quot;);	 scanf(&quot;%d%d&quot;,&amp;amp;a,&amp;amp;b)...]]></description><category></category></item><item><title><![CDATA[编写一个函数，交换两个数的值，要求用指针实现 。函数头部为：void fun(int *x,int *y)]]></title><link>https://blog.youkuaiyun.com/csdn26618/article/details/80030118</link><guid>https://blog.youkuaiyun.com/csdn26618/article/details/80030118</guid><author>csdn26618</author><pubDate>Sat, 21 Apr 2018 15:28:59 +0800</pubDate><description><![CDATA[#include &quot;stdio.h&quot;void fun(int  *x,int  *y){	int t;	t=*x;	*x=*y;	*y=t;		}void main(){	 int a,b;	 printf(&quot;请输入a和b：&quot;);	 scanf(&quot;%d%d&quot;,&amp;amp;a,&amp;amp;b);	 fun(&amp;amp;a,&amp;amp;b);	 printf(&quot;\n\ta = %d ,b = %d\n&quot;,a,]]></description><category></category></item></channel></rss>