【树】leetcode_94_二叉树的中序遍历
c++迭代,
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
vector<int> result;
stack<TreeNode*> re;
while(root!=nullptr || !re.empty()){
while(root!=nullptr){
re.push(root);
root = root->left;
}
if(!re.empty()){
root = re.top();
result.push_back(root->val);
re.pop();
root=root->right;
}
}
return result;
}
};
递归
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<int> inorderTraversal(TreeNode* root) {
vector<int> re;
get_re(root,re);
return(re);
}
void get_re(TreeNode *root, vector<int> &re){
if (root == nullptr){
return;
}
get_re(root->left,re);
re.push_back(root->val);
get_re(root->right,re);
}
};