做法:水,可是被坑...LMT 开到100,还是非递归的使用gcd函数吧...
#include<cstdio>
#include<cstring>
#define LL __int64
//LL(1)<<n
const int LMT=100;
LL dp[LMT][LMT];
bool is[LMT][LMT];
void init(void)
{
memset(is,0,sizeof(is));
memset(dp,0,sizeof(dp));
}
LL gcd(LL a,LL b)
{
LL r=0;
while(b!=0)
{
r=a%b;
a=b;
b=r;
}
return(a);
}
int main(void)
{
int n,m,i,j,cnt,x,y;
LL base,tem;
char sec[LMT];
while(~scanf("%d%d",&n,&m))
{
getchar();
m++;
init();
base=0;
for(i=1;i<=n;++i)
{
gets(sec);
cnt=0;
for(j=0;sec[j];++j)
{
if(sec[j]=='*'||sec[j]=='.')++cnt;
if(sec[j]=='*')is[i][cnt]=1;
}
}
is[0][0]=1;
for(i=1;i<=n+1;i++)is[n+1][i]=1;
dp[0][0]=1;
for(i=0;i<=n;++i)
for(j=0;j<=i;++j)
if(is[i][j])
{
x=i+1;y=j;
if(y)
while(x<=n+1&&y<=x)
{
if(is[x][y])
{
dp[x][y]+=((LL)1<<(x-i-1))*dp[i][j];
break;
}
x+=2;++y;
}
x=i+1;y=j+1;
while(x<=n+1&&y<=x)
{
if(is[x][y])
{
dp[x][y]+=((LL)1<<(x-i-1))*dp[i][j];
break;
}
x+=2;++y;
}
}
for(i=1;i<=n+1;i++)base+=dp[n+1][i];
if(dp[n+1][m]==0)
{
printf("0/%I64d\n",base);
continue;
}
tem=gcd(base,dp[n+1][m]);
printf("%I64d",dp[n+1][m]/tem);
printf("/");
printf("%I64d",base/tem);
printf("\n");
}
return 0;
}