AWR TOP SQL实现

本文详细介绍如何使用Oracle数据库的dba_hist_sqlstat和dba_hist_sqltext视图,通过多种维度(解析次数、执行时间、CPU时间、UserI/O wait、逻辑读、物理读、执行次数)对SQL语句进行性能分析,帮助读者深入理解SQL执行效率的影响因素。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

1 按解析次数排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       sum(parse_calls_delta) parse,
       sum(executions_delta) exec_nums,
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a.parse desc;
2 按执行时间排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       round(sum(elapsed_time_delta)/1000/1000,2) "elapsed_time(s)",
       sum(executions_delta) execs,
       round(sum(elapsed_time_delta)/1000/1000/sum(executions_delta),2)  elapsed_time_per,
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a."elapsed_time(s)" desc;
3 按CPU时间排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       round(sum(cpu_time_delta)/1000/1000,2) "cpu_time",
       sum(executions_delta) execs,
       round(sum(cpu_time_delta)/1000/1000/sum(executions_delta),2)  cpu_time_per,
        round(sum(elapsed_time_delta)/1000/1000,2) "elapsed_time(s)",
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a."cpu_time" desc;
4 按User I/O wait排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       round(sum(iowait_delta)/1000/1000,2) "iowait_time(s)",
       sum(executions_delta) execs,
       round(sum(iowait_delta)/1000/1000/sum(executions_delta),2)  iowait_time_per,
        round(sum(elapsed_time_delta)/1000/1000,2) "elapsed_time(s)",
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a."iowait_time(s)" desc;
5 按逻辑读(gets)排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       round(sum(buffer_gets_delta),2) "buffer_ges",
       sum(executions_delta) execs,
       round(sum(buffer_gets_delta)/sum(executions_delta),2)  iowait_time_per,
        round(sum(elapsed_time_delta)/1000/1000,2) "elapsed_time(s)",
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a."buffer_ges" desc;
7 按物理读(physical read)排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       round(sum(DISK_READS_DELTA),2) "physical_read",
       sum(executions_delta) execs,
       round(sum(DISK_READS_DELTA)/sum(executions_delta),2)  iowait_time_per,
        round(sum(elapsed_time_delta)/1000/1000,2) "elapsed_time(s)",
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a."physical_read" desc;

8 按执行次数排序

select a.*,
       to_char(substr(b.sql_text,1,4000))
from
    (select dhs.sql_id,
       round(sum(executions_delta),2) "exec_num",
       sum(ROWS_PROCESSED_DELTA) row_process,
       round(sum(ROWS_PROCESSED_DELTA)/sum(executions_delta),2)  rows_per_exec,
        round(sum(elapsed_time_delta)/1000/1000,2) "elapsed_time(s)",
       dhs.MODULE
    from dba_hist_sqlstat dhs
    where
        snap_id  > 22438
        and snap_id <= 22440
    group by dhs.sql_id,MODULE) a,
    dba_hist_sqltext b
    where a.sql_id=b.sql_id order by a."exec_num" desc;

来自 “ ITPUB博客 ” ,链接:http://blog.itpub.net/28572479/viewspace-2649803/,如需转载,请注明出处,否则将追究法律责任。

转载于:http://blog.itpub.net/28572479/viewspace-2649803/

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值