分解12/29/2009 输出:29th Dec 2009

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#string #存储 #date #class

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本文介绍了一个简单的Java程序，该程序能够将一系列短日期格式（月/日/年）的数据转换为更易读的形式，包括全称月份、特定日期序数（如1st、2nd等）及完整年份。

class date{
public static void main(String[] args){
  int i=0;
  int j=0;
  String daya = "";//存储天
  String month ="";//存储月
  String year ="";//存储年
  String[] dates = {"07/01/07","09/09/09","07/27/99","12/30/89"};

  for(i=0;i<dates.length;i++){

   System.out.println("<----第"+(i+1)+"组---->");
   System.out.println("dates["+i+"]"+dates[i]);
  String[] day = dates[i].split("[/]");
  for (j=0;j<day.length;j++){
  System.out.println("day["+j+"]"+day[j]);

  }

  //day[0]为月份,将其转换为对应的月份
  if (Integer.parseInt(day[0])<=12 && Integer.parseInt(day[0])>0){//Integer.parseInt(string s)将s强制转换为数字
         String[] months={"Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"};
         month = months[Integer.parseInt(day[0])-1];
         System.out.print(month+" ");
   }

  //day[1]为天,将其转换为对应的天,其中一号二号三号为1st,2nd,3rd,其余加st
  if (Integer.parseInt(day[1])<31 && Integer.parseInt(day[1])>=3){

   daya = day[1]+"th";

  }else{
   if(Integer.parseInt(day[1])==1){daya="1st";}else{
    if(Integer.parseInt(day[1])==2){daya="2nd";}else{
     if(Integer.parseInt(day[1])==3){daya="3rd";}
    }

    }
   }
  System.out.print(daya+" ");

  //day[2]为年,将其转换为2009,1999,如果day[2]<10,则输出200day[2],若day[2]>90,则输出19day[2]
  if(Integer.parseInt(day[2])>80 && Integer.parseInt(day[2])<100){
   year = "19"+day[2];
  }else{
   if(Integer.parseInt(day[2])<10 && Integer.parseInt(day[2])>=0){
    year = "20"+day[2];
   }
  }

  System.out.println(year+" ");
  System.out.println(daya+" "+month+" "+year);

  }
}
}

运行结果:

<----第1组---->
dates[0]07/01/07
day[0]07
day[1]01
day[2]07
Jul 1st 2007
1st Jul 2007
<----第2组---->
dates[1]09/09/09
day[0]09
day[1]09
day[2]09
Sep 09th 2009
09th Sep 2009
<----第3组---->
dates[2]07/27/99
day[0]07
day[1]27
day[2]99
Jul 27th 1999
27th Jul 1999
<----第4组---->
dates[3]12/30/89
day[0]12
day[1]30
day[2]89
Dec 30th 1989
30th Dec 1989