<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[comeonsolo的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/comeonsolo</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; comeonsolo]]></copyright><item><title><![CDATA[Vmware+Centos7.2+Oracle数据库单机实例安装—一步到位]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/82464164</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/82464164</guid><author>comeonsolo</author><pubDate>Fri, 07 Sep 2018 11:03:55 +0800</pubDate><description><![CDATA[准备：

Vmware14pro

下载地址：https://my.vmware.com/web/vmware/details?productId=686&amp;amp;rPId=25457&amp;amp;downloadGroup=WKST1413-WIN

Centos7.2

下载地址：http://archive.kernel.org/centos-vault/7.2.1511/isos/x86_64...]]></description><category></category></item><item><title><![CDATA[Linux 多线程同步问题 条件变量]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/78304554</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/78304554</guid><author>comeonsolo</author><pubDate>Sat, 21 Oct 2017 16:30:51 +0800</pubDate><description><![CDATA[互斥锁：用来上锁。
条件变量：用来等待，当条件变量用来自动阻塞一个线程，直到某特殊情况发生为止。通常条件变量和互斥锁同时使用。
 
函数介绍：
 
1．




名称：


pthread_cond_init




目标：


条件变量初始化




头文件：


#include 




函数原形：


int pth]]></description><category></category></item><item><title><![CDATA[足球赛确定淘汰赛名单-map<string, int>问题]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/78005857</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/78005857</guid><author>comeonsolo</author><pubDate>Sat, 16 Sep 2017 19:45:06 +0800</pubDate><description><![CDATA[科大讯飞笔试题：题意足球赛确定淘汰赛名单 
比赛规则： 
1、参赛队伍为n支， n为偶数。 
2、入围淘汰赛队伍为n/2支。 
3、按积分排名，胜一场积3分，平一场积1分， 负一场积0分，积分相同按净胜球排名，净胜球相同按进球数排名。输入输出第一行为一个整数n，参赛队伍数 
随后n行为球队名字 
随后n*(n-1)/2行为赛事开展情况，格式为 name1-name2 num1:num2 输出n/2行]]></description><category></category></item><item><title><![CDATA[nowcoder-顺时针打印矩阵-模拟魔方逆时针旋转]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77992672</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77992672</guid><author>comeonsolo</author><pubDate>Fri, 15 Sep 2017 15:55:26 +0800</pubDate><description><![CDATA[题目顺时针打印矩阵输入一个矩阵，按照从外向里以顺时针的顺序依次打印出每一个数字，例如，如果输入如下矩阵： 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 则依次打印出数字1,2,3,4,8,12,16,15,14,13,9,5,6,7,11,10.矩阵为：1   2   3   4
5   6   7   8
9   10  11  12  
13  14  15  1]]></description><category></category></item><item><title><![CDATA[LeetCode: -Dynamic Programming-Continuous Subarray Sum[523]]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77942977</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77942977</guid><author>comeonsolo</author><pubDate>Tue, 12 Sep 2017 11:12:42 +0800</pubDate><description><![CDATA[题目非负整数数组中，连续子数组（子数组长度最小为2）和为k的倍数，是否存在的问题。Given a list of non-negative numbers and a target integer k, write a function to check if the array has a continuous subarray of size at least 2 that sums up to]]></description><category></category></item><item><title><![CDATA[LeetCode: -Dynamic Programming-2 Keys Keyboard[650]-复制粘贴问题]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77915008</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77915008</guid><author>comeonsolo</author><pubDate>Sat, 09 Sep 2017 14:16:11 +0800</pubDate><description><![CDATA[题目：一个A，通过复制粘贴操作，实现n个A需要的最少步数。 
每步可以有以下选择： 
1、复制，复制已有的所有A； 
2、粘贴，粘贴上次复制的内容。注意：n的范围在[1， 1000]Initially on a notepad only one character ‘A’ is present. You can perform two operations on this notepad for e]]></description><category></category></item><item><title><![CDATA[LeetCode: -Dynamic Programming-Maximum Subarray[53]-子数组最大和]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77913887</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77913887</guid><author>comeonsolo</author><pubDate>Sat, 09 Sep 2017 11:17:24 +0800</pubDate><description><![CDATA[Find the contiguous subarray within an array (containing at least one number) which has the largest sum.For example, given the array [-2,1,-3,4,-1,2,1,-5,4],
the contiguous subarray [4,-1,2,1] has the]]></description><category></category></item><item><title><![CDATA[LeetCode: -Dynamic Programming-Best Time to Buy and Sell Stock[121]]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77895529</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77895529</guid><author>comeonsolo</author><pubDate>Fri, 08 Sep 2017 15:40:09 +0800</pubDate><description><![CDATA[Say you have an array for which the ith element is the price of a given stock on day i.If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), desi]]></description><category></category></item><item><title><![CDATA[LeetCode: -Dynamic Programming-House Robber[198]]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77895106</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77895106</guid><author>comeonsolo</author><pubDate>Fri, 08 Sep 2017 15:14:18 +0800</pubDate><description><![CDATA[求非负整数数组中取一些元素的和的最大值，要求不能取相邻的元素You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each o]]></description><category></category></item><item><title><![CDATA[Linux 学习笔记--持续更新]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77879198</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77879198</guid><author>comeonsolo</author><pubDate>Thu, 07 Sep 2017 11:25:57 +0800</pubDate><description><![CDATA[常见的Linux发行版本都有 
常见的Linux发现版本有Redhat、Centos、Debian、Ubuntu、Suse 
Redhat官网：www.redhat.com 
Centos官网：www.centos.org 
Ubuntu官网：www.ubuntu.org.cnLinux开机启动流程详细步骤是什么？系统安装完，忘记密码如何破解？开机步骤由a–h 
a、首先是bios加电自检、初始化，]]></description><category></category></item><item><title><![CDATA[C++ const 限定符]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77844739</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77844739</guid><author>comeonsolo</author><pubDate>Mon, 04 Sep 2017 23:13:37 +0800</pubDate><description><![CDATA[定义与初始化有时我们希望定义这样一个变量，它的值不能被改变。const int bufSize = 512;    //输入bufSize的大小
bufSize = 512；              // **错误**!!试图向const对象写值const int j = get_size();   //正确，运行时初始化
const int j = 42;           //正确，编译时初]]></description><category></category></item><item><title><![CDATA[LeetCode: -Dynamic Programming-Strange Printer[664]]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77839117</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77839117</guid><author>comeonsolo</author><pubDate>Mon, 04 Sep 2017 16:43:07 +0800</pubDate><description><![CDATA[题目一个打印机，每一轮能打印一个同一个字符的序列，能在下一轮在任何位置开始任何位置结束打印一个其他的字符。后打印的将覆盖先打印的。 
给定一个字符串，求最小的打印轮次。示例：Input: "aaabbb"
Output: 2
Explanation: 先打印 "aaa" 再打印 "bbb".Input: "aba"
Output: 2
Explanation: 先打印 "aaa" 再从第二个位置打印]]></description><category></category></item><item><title><![CDATA[将字符串划分为单词—阿里2017笔试编程题]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77778561</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77778561</guid><author>comeonsolo</author><pubDate>Fri, 01 Sep 2017 21:46:57 +0800</pubDate><description><![CDATA[添加最少空格]]></description><category></category></item><item><title><![CDATA[C++输入获取未知长度的行输入数组 与 输出控制]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77778436</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77778436</guid><author>comeonsolo</author><pubDate>Fri, 01 Sep 2017 21:35:51 +0800</pubDate><description><![CDATA[C++输入获取未知长度的行输入数组 与 输出控制]]></description><category></category></item><item><title><![CDATA[C/C++的四大内存分区]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77258776</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77258776</guid><author>comeonsolo</author><pubDate>Wed, 16 Aug 2017 17:36:03 +0800</pubDate><description><![CDATA[导读

正确的理解C/C++程序的内存分区，是合格程序猿的基本要求。 
网络上流形两大版本内存分区，分别为：

1. 五大内存分区：堆、栈、全局/静态存储区、自由存储区和常量存储区。 
2. 五大内存分区：堆、栈、全局/静态存储区、字符串常量区和代码区。

且不论以上两种分区孰是孰非，孰优孰劣，我认为具体的内存分区和编译器有很大关系，我想不同编译器对内存的划分都不尽相同，但也大同小]]></description><category></category></item><item><title><![CDATA[三次握手]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77149605</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77149605</guid><author>comeonsolo</author><pubDate>Sun, 13 Aug 2017 20:16:17 +0800</pubDate><description><![CDATA[参照：
http://course.ccniit.com/CSTD/Linux/reference/files/018.PDF
http://hi.baidu.com/raycomer/item/944d23d9b502d13be3108f61
 
建立连接： 
理解：窗口和滑动窗口
TCP的流量控制

TCP使用窗口机制进行流量控制
什么是窗口？
连接建立时，各端分配一块缓冲区用]]></description><category></category></item><item><title><![CDATA[URL访问过程]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77149451</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77149451</guid><author>comeonsolo</author><pubDate>Sun, 13 Aug 2017 20:00:55 +0800</pubDate><description><![CDATA[输入 URL：http://www.baidu.comDNS 域名解析计算机无法识别域名，计算机与计算机之间要想进行通信，必须通过ip地址用来定位该计算机所在的位置在浏览器中，输入的ip地址或者域名，默认给你加了一个80端口号（对方的服务器监听的就是80端口）158.12.25.652 域名就是为了好记为了好记，所以我们的万维网提供了 一个 域名这样的概念当你输入了 ip 地址后，浏览器会自动去 ]]></description><category></category></item><item><title><![CDATA[OSI7层模型与TCP/IP协议栈4层]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/77149424</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/77149424</guid><author>comeonsolo</author><pubDate>Sun, 13 Aug 2017 19:57:44 +0800</pubDate><description><![CDATA[osi（Open System Interconnection Reference Model）


osi7层模型，分别是


第7层 应用层（Application Layer）
提供为应用软件而设的界面，以设置与另一应用软件之间的通信。例如：HTTP,HTTPS，FTP，TELNET，SSH，SMTP，POP3等。


第6层 表示层（Presentation Layer]]></description><category></category></item><item><title><![CDATA[C++Container之vector用法]]></title><link>https://blog.youkuaiyun.com/comeonsolo/article/details/62072653</link><guid>https://blog.youkuaiyun.com/comeonsolo/article/details/62072653</guid><author>comeonsolo</author><pubDate>Tue, 14 Mar 2017 22:47:20 +0800</pubDate><description><![CDATA[C++Container之vector用法标准库类型vector表示类型相同的对象的集合。该对象包括 除引用外 大多数内置类型和类类型，甚至组成vector的元素也可以是vector头文件 
    #include<vector> 
    using std::vector;
定义和初始化 
    vector<int> ivec;  //ivec保存int类型的对象 
    vector<]]></description><category></category></item></channel></rss>