A+B Format (20)

最新推荐文章于 2018-08-06 12:49:11 发布

原创最新推荐文章于 2018-08-06 12:49:11 发布 · 509 阅读

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本文介绍了一个简单的程序，用于计算两个整数的和，并将结果以标准格式输出，标准格式要求每三位数字用逗号分隔。程序首先读取两个整数，计算它们的和，然后通过判断是否为负数来进行相应的格式调整，最后输出格式化的结果。

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Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991

#include<iostream>
using namespace std;
int main()
{




	int N,M;
	while(scanf("%d%d",&N,&M)!=EOF)
	{
	   int total=N+M;
	   bool isminus=false;
	   if(total<0)
	   {
	      total=(-1)*total;
		  isminus=true;


	   }
	   
       int parts[5];
	   int len=0;
	   if(total<1000)
	   {
	     parts[len]=total;
		 total=0;
		 len++;
	   }
	   while(total!=0)
	   {
		   parts[len]=total%1000;
		   total=total/1000;
	       len++;
	   }
	  
	  
		   len--;
	   if(isminus)
		   cout<<"-";
	   if(len!=0)
	   cout<<parts[len]<<",";
	   else cout<<parts[len]<<endl;
	   for(int i=len-1;i>0;i--)
	   {
		   if(parts[i]<10)
	         cout<<"00"<<parts[i]<<",";
		   else if(parts[i]<100)
                cout<<"0"<<parts[i]<<",";
		   else 
                cout<<parts[i]<<",";
	   }
	   if(len!=0)
	   { if(parts[0]<10)
	         cout<<"00"<<parts[0]<<endl;
		   else if(parts[0]<100)
                cout<<"0"<<parts[0]<<endl;
		   else 
                cout<<parts[0]<<endl;
	   }
	 


	}
  return 0;
}