[LeetCode] Combinations, Solution

最新推荐文章于 2021-02-24 07:35:30 发布

原创最新推荐文章于 2021-02-24 07:35:30 发布 · 148 阅读

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本文介绍了一个经典的组合问题：从1到n中选择k个数的所有可能组合，并提供了一种递归算法来解决这个问题。该算法通过不断添加数字并检查是否达到终止条件（选择的数字数量等于k）来生成所有可能的组合。

Given two integers n and k, return all possible combinations of k numbers out of 1 … n.

For example,
If n = 4 and k = 2, a solution is:

[
  [2,4],
  [3,4],
  [2,3],
  [1,2],
  [1,3],
  [1,4],
]

» Solve this problem

[Thoughts]
Similar as “Conbination Sum”. But here the terminate condition is “k”, not sum.

[Code]

1:    vector<vector<int> > combine(int n, int k) {  
2:      // Start typing your C/C++ solution below  
3:      // DO NOT write int main() function  
4:      vector<vector<int> > result;  
5:      vector<int> solution;  
6:      GetCombine(n,k,1, solution, result);  
7:      return result;  
8:    }  
9:    void GetCombine(  
10:      int n,   
11:      int k,   
12:      int level,  
13:      vector<int>& solution,  
14:      vector<vector<int> >& result)  
15:    {      
16:      if(solution.size() == k)  
17:      {  
18:        result.push_back(solution);  
19:        return;  
20:      }  
21:      for(int i =level; i<= n; i++)  
22:      {  
23:        solution.push_back(i);  
24:        GetCombine(n,k,i+1, solution, result);  
25:        solution.pop_back();  
26:      }  
27:    }