1042 Shuffling Machine (20 point(s))

最新推荐文章于 2025-06-25 15:17:39 发布

原创最新推荐文章于 2025-06-25 15:17:39 发布 · 160 阅读

0 ·

CC 4.0 BY-SA版权

PAT 专栏收录该内容

138 篇文章

订阅专栏

本文介绍了一种模拟洗牌机工作的算法，通过给定的随机顺序对一副包含54张牌的扑克进行洗牌，包括从标准的顺序到指定次数后的洗牌结果。算法使用辅助数组存储每次洗牌结果，并在输出时转换牌面字符。

1042 Shuffling Machine (20 point(s))

Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.

The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:

S1, S2, ..., S13, 
H1, H2, ..., H13, 
C1, C2, ..., C13, 
D1, D2, ..., D13, 
J1, J2

where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer K (≤20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.

Sample Input:

2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47

Sample Output:

S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5

模拟题。最开始没有读懂题意，走了弯路。

注意点：

1. 用辅助数组temp[]存储每一次的洗牌的结果。

2. 输出的时候，注意逻辑关系。

#include<stdio.h>
int main(void){
	int K;scanf("%d",&K);
	int cards[55];
	int machine[55];
	int temp [55];
	for(int i=1;i<=54;i++){
		cards[i] = i;
		scanf("%d",&machine[i]);
	}
	while(K--){
		for(int i = 1;i<=54;i++){
			temp[machine[i]] = cards[i];
		}
		for(int i = 1;i<=54;i++){
			cards[i] = temp [i];
		}
	}
	char L[5]={'S','H','C','D','J'};
	for(int i=1;i<=54;i++){
		if(i==1) printf("%c%d",L[(cards[i]-1)/13],cards[i]-13*(int)((cards[i]-1)/13));
		else printf(" %c%d",L[(cards[i]-1)/13],cards[i]-13*(int)((cards[i]-1)/13));
	}
	printf("\n");return 0;
}

代码写法有借鉴于：https://blog.youkuaiyun.com/qq_40204582/article/details/86634212