UVA100 The 3n + 1 problem

解决linux 2.5G网卡驱动问题 解决linux 2.5G网卡驱动问题 关键词:2.5G网卡驱动,ubuntu,安装,2.5G Ethernet LINUX driver,Realtek网卡驱动 由于2.5G网卡较新,各linux发行版的通用驱动已不适用,新装的系统会出现无法上网问题,由于国内网络环境去Realtek官网很难下载到驱动文件,故本文提供github上的2.5G Ethernet LINUX driver r8125 for kernel up to 5.6的版本驱动文件r8125-9.003.05.tar.bz2各位可以自 阅读详情


Background

Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.

The Problem

Consider the following algorithm:

 
		1. 		 input n

2. print n

3. if n = 1 then STOP

4. if n is odd then tex2html_wrap_inline44

5. else tex2html_wrap_inline46

6. GOTO 2

Given the input 22, the following sequence of numbers will be printed 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

It is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1,000,000 (and, in fact, for many more numbers than this.)

Given an input n, it is possible to determine the number of numbers printed (including the 1). For a given nthis is called the cycle-length of n. In the example above, the cycle length of 22 is 16.

For any two numbers i and j you are to determine the maximum cycle length over all numbers between i and j.

The Input

The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 1,000,000 and greater than 0.

You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j.

You can assume that no operation overflows a 32-bit integer.

The Output

For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).

Sample Input

1 10
100 200
201 210
900 1000

Sample Output

1 10 20
100 200 125
201 210 89
900 1000 174

注意:(1)i和j的大小关系
     (2)3*n+1的值可能会超过int
参考代码:
#include <stdio.h>
typedef long long ll;
int main(){
	ll i,j;
	while (~scanf("%lld%lld",&i,&j)){
		ll ii=i,jj=j;
		int max=0;
		if (i>j){
			ll temp=j;
			j=i;
			i=temp;
		}
		for (ll y=i;y<=j;y++){
			ll x=y;
			int count=1;
		//	printf("%lld ",x);
			while (x!=1){
				count++;
				if (x%2!=0)
					x=3*x+1;
				else
					x=x/2;
			//	printf("%lld ",x);
			}
		//	printf("\n");
			if (max<count)
				max=count;
		}
		printf("%lld %lld %d\n",ii,jj,max);
	}
	return 0;
}


Background

Problems in Computer Science are often classified as belonging to a certain class of problems (e.g., NP, Unsolvable, Recursive). In this problem you will be analyzing a property of an algorithm whose classification is not known for all possible inputs.

The Problem

Consider the following algorithm:

 
		1. 		 input n

2. print n

3. if n = 1 then STOP

4. if n is odd then tex2html_wrap_inline44

5. else tex2html_wrap_inline46

6. GOTO 2

Given the input 22, the following sequence of numbers will be printed 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

It is conjectured that the algorithm above will terminate (when a 1 is printed) for any integral input value. Despite the simplicity of the algorithm, it is unknown whether this conjecture is true. It has been verified, however, for all integers n such that 0 < n < 1,000,000 (and, in fact, for many more numbers than this.)

Given an input n, it is possible to determine the number of numbers printed (including the 1). For a given nthis is called the cycle-length of n. In the example above, the cycle length of 22 is 16.

For any two numbers i and j you are to determine the maximum cycle length over all numbers between i and j.

The Input

The input will consist of a series of pairs of integers i and j, one pair of integers per line. All integers will be less than 1,000,000 and greater than 0.

You should process all pairs of integers and for each pair determine the maximum cycle length over all integers between and including i and j.

You can assume that no operation overflows a 32-bit integer.

The Output

For each pair of input integers i and j you should output i, j, and the maximum cycle length for integers between and including i and j. These three numbers should be separated by at least one space with all three numbers on one line and with one line of output for each line of input. The integers i and j must appear in the output in the same order in which they appeared in the input and should be followed by the maximum cycle length (on the same line).

Sample Input

1 10
100 200
201 210
900 1000

Sample Output

1 10 20
100 200 125
201 210 89
900 1000 174

注意:(1)i和j的大小关系
     (2)3*n+1的值可能会超过int
参考代码:
COMSOL介电弹性体数值仿真指南:预拉伸圆形DEA的稳态变形分析(II) 本期博客是《COMSOL介电弹性体数值仿真指南》系列博客中的一期。聚焦于介电弹性体驱动器(DEA)中最为经典的预拉伸圆形DEA驱动器构型,对其在COMSOL平台中的具体建模步骤进行介绍与讨论。 阅读详情

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