Where is the Marble?
| Where is the Marble? |
Raju and Meena love to play with Marbles. They have got a lot of marbles with numbers written on them. At the beginning, Raju would place the marbles one after another in ascending order of the numbers written on them. Then Meena would ask Raju to find the first marble with a certain number. She would count 1...2...3. Raju gets one point for correct answer, and Meena gets the point if Raju fails. After some fixed number of trials the game ends and the player with maximum points wins. Today it's your chance to play as Raju. Being the smart kid, you'd be taking the favor of a computer. But don't underestimate Meena, she had written a program to keep track how much time you're taking to give all the answers. So now you have to write a program, which will help you in your role as Raju.
Input
There can be multiple test cases. Total no of test cases is less than 65. Each test case consists begins with 2 integers: N the number of marbles and Q the number of queries Mina would make. The next N lines would contain the numbers written on the N marbles. These marble numbers will not come in any particular order. Following Q lines will have Q queries. Be assured, none of the input numbers are greater than 10000 and none of them are negative.
Input is terminated by a test case where N = 0 and Q = 0.
Output
For each test case output the serial number of the case.
For each of the queries, print one line of output. The format of this line will depend upon whether or not the query number is written upon any of the marbles. The two different formats are described below:
- `x found at y', if the first marble with number x was found at position y. Positions are numbered 1, 2,..., N.
- `x not found', if the marble with number x is not present.
Look at the output for sample input for details.
Sample Input
4 1 2 3 5 1 5 5 2 1 3 3 3 1 2 3 0 0
Sample Output
CASE# 1: 5 found at 4 CASE# 2: 2 not found 3 found at 3
======================================
直接排个序看它是第几个就行了
#include <iostream>
#include <cstdio>
#include <algorithm>
using namespace std;
int n,q,a[11111];
int main()
{
int t=0,x;
while(~scanf("%d%d",&n,&q))
{
if(n==0&&q==0) break;
printf("CASE# %d:\n",++t);
for(int i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
sort(a,a+n);
for(int i=0;i<q;i++)
{
int ok=0;
scanf("%d",&x);
for(int i=0;i<n;i++)
{
if(x==a[i])
{
printf("%d found at %d\n",x,i+1);
ok=1;
break;
}
}
if(!ok) printf("%d not found\n",x);
}
}
return 0;
}

这是一个编程挑战,玩家需要帮助Raju在一个升序排列的带有编号的大理石集合中快速找到特定编号的大理石。游戏通过输入一系列测试案例来进行,每个案例包括一组大理石及其编号,以及需要查询的编号列表。任务是编写一个程序来确定每个查询编号对应的大理石位置。
465

被折叠的 条评论
为什么被折叠?



