Difficulty: 3
Frequency: 3
Problem:
Given a binary tree
struct TreeLinkNode { TreeLinkNode *left; TreeLinkNode *right; TreeLinkNode *next; }
Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to NULL
.
Initially, all next pointers are set to NULL
.
Note:
- You may only use constant extra space.
- You may assume that it is a perfect binary tree (ie, all leaves are at the same level, and every parent has two children).
For example,
Given the following perfect binary tree,
1 / \ 2 3 / \ / \ 4 5 6 7
After calling your function, the tree should look like:
1 -> NULL / \ 2 -> 3 -> NULL / \ / \ 4->5->6->7 -> NULL
Solution:
/**
* Definition for binary tree with next pointer.
* struct TreeLinkNode {
* int val;
* TreeLinkNode *left, *right, *next;
* TreeLinkNode(int x) : val(x), left(NULL), right(NULL), next(NULL) {}
* };
*/
class Solution {
public:
void connect(TreeLinkNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
connectPerfectRecursive(root);
}
void connectPerfectRecursive(TreeLinkNode * root)
{
if (root==NULL)
return;
if (root->left==NULL)
{
root->next = NULL;
return;
}
connectPerfectRecursive(root->left);
connectPerfectRecursive(root->right);
TreeLinkNode *left = root->left, *right = root->right;
while(left!=NULL)
{
left->next = right;
left = left->right;
right = right->left;
}
}
};
Notes:
Although my code passed all tests, I still don't understand the requirement: you may only use constant extra space. In this case, I think tree traverse is necessary. Tree traverse is either recursive or using a stack. Neither of them meets the constant extra space requirement. I will consult others' codes later.