Python Cookbook读书笔记—利用*实现精巧递归

以下为源代码：

item = [1, 10, 7, 4, 5, 9]

def sum(item):
    head, *tail = item
    return head + sum(tail) if tail else head

print(f"sum = {sum(item)}")

一下为输出结果：

PS C:\Users\zoro.zhang> & C:/Users/zoro.zhang/AppData/Local/Programs/Python/Python39-32/python.exe e:/Python/Book/Python_Cookbook/recurve.py
sum = 36