http 含有空格

通常我们在传递一个地址时如果有空格

String myString = "http://myhost.com/media/mp3s/9/Agenda of swine - 13. Persecution Ascension_ leave nothing standing.mp3"; 
URI myUri = new URI(myString); 
结果会抛出异常

java.net.URISyntaxException: Illegal character in path at index X 

 

其实很简单 只要把空格转换成别的字符就可以了

这里加设有空格的只在最后一个\ 后面

URI uri = new URI(string.replace(' ', '+')); 
或者

URI uri = new URI(string.replace(" ", "%20")); 
然后

int pos = string.lastIndexOf('/') + 1; 
URI uri = new URI(string.substring(0, pos) + URLEncoder.encode(string.substring(pos), "UTF-8"));