转圈打印数组

#include <stdio.h>

int main(){

    int n=4;

    int a[4][4] = {{1,2,3,4},{4,5,6,7},{7,8,9,10},{11,12,13,14}};

    int i = 0;
    int j = 0;

    for ( i=0; i< n; i ++){
        for(j = 0; j < n;j++){
            printf("%d ", a[i][j]);
        }
        printf("\n");
    }


    int k =0;
    i =  j = 0;
    printf("\n");

    int ul = 0;
    int ur = n;

    while( k < 2){

       for(; j < (n-k) ;j++){
           printf("行a[%d][%d] %d ",i,j, a[i][j]);
       }

       j-=1;

       // printf("\n %d %d \n", a[1][2],a[2][2]);

       i = i+1;
        // j = j;
       for (; i < (n-k); i++){
            printf("列a[%d][%d] %d ",i,j, a[i][j]); 
       }

       i-=1;
       //j = j - 1;
       j-=1;

       for(; j >= k; j--){
           printf("底行%d ", a[i][j]);
       }

       j+=1;

       //j+=1;
       i = i - 1;
       for( ; i > k; i--){
           printf("左列%d ", a[i][j]);
       }

       i+=1;
       j+=1;

       k = k+1;
    }
}

转载于:https://my.oschina.net/innovation/blog/3073119