题目1 : String reorder
-
aabbccdd 007799aabbccddeeff113355zz 1234.89898 abcdefabcdefabcdefaaaaaaaaaaaaaabbbbbbbddddddee
样例输出 -
abcdabcd 013579abcdefz013579abcdefz <invalid input string> abcdefabcdefabcdefabdeabdeabdabdabdabdabaaaaaaa
-
用map比较好,这个程序耗时太多,哎。。。
-
代码如下:
Description
For this question, your program is required to process an input string containing only ASCII characters between ‘0’ and ‘9’, or between ‘a’ and ‘z’ (including ‘0’, ‘9’, ‘a’, ‘z’).
Your program should reorder and split all input string characters into multiple segments, and output all segments as one concatenated string. The following requirements should also be met,
1. Characters in each segment should be in strictly increasing order. For ordering, ‘9’ is larger than ‘0’, ‘a’ is larger than ‘9’, and ‘z’ is larger than ‘a’ (basically following ASCII character order).
2. Characters in the second segment must be the same as or a subset of the first segment; and every following segment must be the same as or a subset of its previous segment.
Your program should output string “<invalid input string>” when the input contains any invalid characters (i.e., outside the '0'-'9' and 'a'-'z' range).
Input
Input consists of multiple cases, one case per line. Each case is one string consisting of ASCII characters.
Output
For each case, print exactly one line with the reordered string based on the criteria above.
#include <iostream> //#include <map> #include <vector> #include <list> #include <algorithm> #include <string> using namespace std; bool checkstr(string a) { for (unsigned int i=0;i<a.size();i++) { if (a[i]<'0'||a[i]>'z'||('9'<a[i]&&a[i]<'a')) { return false; } } return true; } int main() { string sa; vector<string> va; list<char>::iterator it1; //while(cin>>sa) while(getline(cin,sa)) { va.push_back(sa); } vector<list<char> > la(va.size()); for (unsigned int i=0;i<va.size();i++) { for (unsigned int j=0;j<va[i].size();j++) { la[i].push_back(va[i][j]); } la[i].sort(); } for (unsigned int i=0;i<va.size();i++) { if (checkstr(va[i])) { char temp; it1=la[i].begin(); while (!la[i].empty()) { cout<<*it1; temp=*it1; it1=la[i].erase(it1); if (it1==la[i].end()&&!la[i].empty()) { it1=la[i].begin(); } while(!la[i].empty()&&*it1==temp) { ++it1; if (it1==la[i].end()&&!la[i].empty()) { it1=la[i].begin(); } } } cout<<endl; } else cout<<"<invalid input string>"<<endl; } //system("pause"); return 0; }
本文介绍了一种处理特定范围ASCII字符('0'-'9'及'a'-'z')的字符串重组算法。该算法将输入字符串按字符递增顺序重新排列,并分成多个段落输出。每个后续段落必须是前一个段落的子集。若输入包含无效字符,则返回错误信息。
886

被折叠的 条评论
为什么被折叠?



