出处
http://www.programcreek.com/2014/07/leetcode-implement-queue-using-stacks-java/
http://blog.youkuaiyun.com/xudli/article/details/46784153
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
- You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
//第一种写法对于pop以及peek还有判断是否为空比较方便,都是直接在value上边判断的
//第二种虽然操作看起来比第一种貌似稍微麻烦一些,其实懂得了原理之后,会发现很不错,移动元素次数应该比第一种少
/*class MyQueue {
// Push element x to the back of queue.
Stack<Integer> temp=new Stack<Integer>();//临时中转的栈
Stack<Integer> value=new Stack<Integer>();//真正保存数据的栈
public void push(int x) {
if(value.isEmpty())
value.push(x);//第一个入栈的元素
else{
while(!value.isEmpty())
temp.push(value.pop());//循环把value中的元素临时转移到temp
value.push(x);//把新入的那个元素放入value栈底
while(!temp.isEmpty())
value.push(temp.pop());//再循环把上上步移到temp的元素转移回value
}
}//静心根据栈的后进先出特性,画一下流程就能很清楚的知道实现了队列的先进先出
// Removes the element from in front of queue.
public void pop() {
value.pop();
}
// Get the front element.
public int peek() {
return value.peek();
}
// Return whether the queue is empty.
public boolean empty() {
return value.isEmpty();
}
}*/
class MyQueue {//才发现在leetcode里边,不把这个class前边的空格删除是会报错的
Stack<Integer> s1 = new Stack<>(); //s1是用来放新进来的元素的Stack<Integer> s2 = new Stack<>();
// Push element x to the back of queue.
public void push(int x) {
s1.push(x);
}
// Removes the element from in front of queue.
public void pop() {
if(!s2.isEmpty()) s2.pop();
else {
while(!s1.isEmpty()) s2.push(s1.pop());
s2.pop();
}
}
// Get the front element.
public int peek() {
if(!s2.isEmpty()) return s2.peek();
else {
while(!s1.isEmpty()) s2.push(s1.pop());
return s2.peek();
}
}
// Return whether the queue is empty.
public boolean empty() {
return s1.empty() && s2.empty();
}
}