public boolean isPail(ListNode head) {
ListNode slow = head;
ListNode fast = head;
while (fast != null && fast.next != null) {
fast = fast.next.next;
slow = slow.next;
}
ListNode curr1 = reverse(slow);
ListNode curr2 = head;
while (curr1 != null) {
if (curr1.val!= curr2.val) {
return false;
}
curr1 = curr1.next;
curr2 = curr2.next;
}
return true;
}
private ListNode reverse(ListNode node) {
ListNode prev = null;
ListNode curr = node;
while (curr != null) {
ListNode temp = curr.next;
curr.next = prev;
prev = curr;
curr = temp;
}
return prev;
}
本文介绍了一种高效的链表回文检测算法。通过快慢指针找到链表中点,将后半部分链表反转,然后比较前后两部分是否相同来判断整个链表是否为回文。该方法无需额外空间。

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