c语言实现谷歌笔试题：返回参数二进制中1的个数

#include <stdio.h>

int count_one_bits(int num)
{
	int count = 0;
	while(num)
	{
		count++;
		num = num&(num-1);
	}
	return count;
}

int main()
{
	int num = -1;
	printf("count = %d\n", count_one_bits(num));
	
	return 0;
}