题目描述
Fibonacci数列定义为(1,1,2,3,5,8,.....),即每个元素是前两个元素的和。如果一个Fibonacci数与所有小于它的Fibonacci数互质,那么称之为Fibonacci质数。 现在要求你输出前n个Fibonacci数 The Fibonacci Numbers {0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ...} are defined by the recurrence: F(0)=0 F(1)=1 F(i)=F(i-1)+F(i-2) Write a program to calculate the Fibonacci Numbers.
输入
The first line of the input file contains a single integer T, the number of test cases. The following T lines,each contains an integer n ( 0 <= n <= 45 ), and you are expected to calculate Fn.
输出
Output Fn on a separate line.
样例输入 Copy
5 0 3 5 9 20
样例输出 Copy
0 2 5 34 6765
本人代码如下:
#include<stdio.h>
int main()
{
int n,a[50];
a[0]=0;
a[1]=1;
for(int i=2;i<50;i++)
a[i]=a[i-1]+a[i-2];
scanf("%d",&n);
int b[n];
for(int i=0;i<n;i++)
scanf("%d",&b[i]);
for(int i=0;i<n-1;i++)
printf("%d\n",a[b[i]]);
printf("%d",a[b[n-1]]);
return 0;
}