fragment onactivityresult 回调异常

最新推荐文章于 2025-12-15 09:49:56 发布

原创最新推荐文章于 2025-12-15 09:49:56 发布 · 119 阅读

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文章标签：

#android #java #开发语言

该文章介绍了一种处理Fragment回调异常的解决方案，通过在基类FragmentActivity中重写onActivityResult方法，遍历并递归调用所有Fragment及其子Fragment的onActivityResult，确保每个Fragment都能正确接收和处理结果。

回调异常解决办法:

fragment onactivityresult

public class MyBaseFragmentActivity extends FragmentActivity
{
    private String TAG="MyBaseFragmentActivity";
    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) 
    {
        super.onActivityResult(requestCode, resultCode, data);
        FragmentManager fragmentManager=getSupportFragmentManager();
        for(int indext=0;indext<fragmentManager.getFragments().size();indext++)
        {
            Fragment fragment=fragmentManager.getFragments().get(indext); //找到第一层Fragment
            if(fragment==null)
                 Log.w(TAG, "Activity result no fragment exists for index: 0x"  
                         + Integer.toHexString(requestCode));  
            else 
                handleResult(fragment,requestCode,resultCode,data);
        }
    }
    /**
     * 递归调用，对所有的子Fragment生效
     * @param fragment
     * @param requestCode
     * @param resultCode
     * @param data
     */
    private void handleResult(Fragment fragment,int requestCode,int resultCode,Intent data) 
    {
        fragment.onActivityResult(requestCode, resultCode, data);//调用每个Fragment的onActivityResult
        Log.e(TAG, "MyBaseFragmentActivity");
        List<Fragment> childFragment = fragment.getChildFragmentManager().getFragments(); //找到第二层Fragment 
        if(childFragment!=null)
            for(Fragment f:childFragment)
                if(f!=null)
                {
                    handleResult(f, requestCode, resultCode, data);
                }
        if(childFragment==null)
            Log.e(TAG, "MyBaseFragmentActivity1111");
    }

}