filter(函数,列表)过滤
对列表做过滤
将列表中,每个值对于函数返回值为True的时候,保留
比如:将>5 的值取出来。
>>> def f(x):
... if x > 5:
... return True
...
>>> f(6)
True
>>> f(1)
>>> l = range(10)
>>> filter(f,l)
[6, 7, 8, 9]
zip()并行遍历、 map()
当列表长度不一样的时候,zip会取最短的长度
但是map会用None填充
>>> name = ["a",'b','c']
>>> age = [1,2,3]
>>> tel = ['11','22','33']
>>> zip(name,age,tel)
[('a', 1, '11'), ('b', 2, '22'), ('c', 3, '33')]
>>> map(None,name,age,tel)
[('a', 1, '11'), ('b', 2, '22'), ('c', 3, '33')]
>>> test=[1,2]
>>> zip(name,test)
[('a', 1), ('b', 2)]
>>> map(None,name,test)
[('a', 1), ('b', 2), ('c', None)]
>>> a =[1,2,3]
>>> b = [4,5,6]
>>> def mf(x,y):
... return x*y
...
>>> map(mf,a,b)
[4, 10, 18]
reduce()
>>> l = range(100)
>>> reduce(lambda x,y:x+y,l)
4950
不用for循环了,更加简练了