Leetcode:Remove Element

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

public int removeElement(int[] A, int elem) {

    }

给你一个数组，和一个值，移除所有该值的元素，返回新长度。

数组元素顺序可变，只要返回正确的新长度即可。

    public int removeElement(int[] A, int elem) {
        if(A.length==0) return 0;
        int p=0;
        for(int i=0;i<A.length;i++){
            if(A[i]!=elem){
                A[p++]=A[i];
            }
        }
        return p;
    }